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Reaction
2AgNO₃ + Cu ⇒ Cu(NO₃)₂ + 2Ag
mol silver (Ag): 95.3 : 108 g/mol = 0.882
mol copper nitrate (Cu(NO₃)₂): 82.9 : 187.5 g/mol = 0.441
mol Ag = 2 x mol Cu(NO₃)₂, so 0.441 being the mole basis of the reactants
mol Cu = 0.441
mass Cu = 0.441 x 63.5 g/mol = 28 g
mol AgNO₃ = 0.882
mass AgNO₃ = 0.882 x 170 g/mol = 149.94 g
Answer:
a) 128 grams
b) 81.25%
Explanation:
a) The mixture will be between the alloy and the pure copper, so the mass will be the sum of the mass of the compounds:
m = 50 + 78 = 128 g
b) In the alloy, 52% is copper, so to know the mass of copper in the alloy, we must multiply the total mass by 52% (which is 0.52)
0.52x50 = 26 g of copper
The total mass of copper in the mixture is 26 + 78 = 104 g
So, the percentual of copper is the mass of copper divided by the total mass
104/128 = 0.8125
Multiplying by 100%, to have the result in percentage
0.8125x100% = 81.25%
Answer:
no of formula unit = 
Explanation:
atomic mass of CaCl2 = 40 + 2×35.5 = 111 g.
no of formula unit = no of moles × Avagadro number
=
