What is the molarity of a solution where there are 1.35 moles of H2SO4 in 3.00 L of solution?

Chemistry

1 answer:

Montano1993 [528]2 years ago

4 0

Answer: 0.450 M H2SO4

Explanation:

To solve this problem, we must remember how to compute molarity. To find the molarity of a solution, we divide the number of moles by the number of liters of solution. Using this formula and substituting the given values, we get:

Molarity = moles solute/liters solution

= 1.35 moles/3.00 L

= 0.450 M H2SO4

Therefore, the correct answer is 0.450 M H2SO4. Note that the answer has 3 significant figures because each of the given values also contains 3 significant figures.

Hope this helps!

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<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$molarity=\frac{number of moles}{volume}$