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AveGali [126]
3 years ago
8

What is the molarity of a solution where there are 1.35 moles of H2SO4 in 3.00 L of solution?

Chemistry
1 answer:
Montano1993 [528]3 years ago
4 0

Answer: 0.450 M H2SO4

Explanation:

To solve this problem, we must remember how to compute molarity. To find the molarity of a solution, we divide the number of moles by the number of liters of solution. Using this formula and substituting the given values, we get:

Molarity = moles solute/liters solution

= 1.35 moles/3.00 L

= 0.450 M H2SO4

Therefore, the correct answer is 0.450 M H2SO4. Note that the answer has 3 significant figures because each of the given values also contains 3 significant figures.

Hope this helps!

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2. A sample of gas has a pressure of 195 kPa and a volume of 3.50 L. If the pressure
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<h2>4.55 L</h2>

Explanation:

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Read 2 more answers
A sample of nitrogen occupies 10.0 liters at 25°C what would be the new volume at 20°C? 7.9 L Ob 9.8 L 10.2 L 10.6 L
PtichkaEL [24]

Answer:

  9.4 liter

Explanation:

1) Data:

V₁ = 10.0 L

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  V₂ = ?

2) Formula:

Used combined law of gases:

  PV / T = constant

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3) Solution:

Solve the equation for V₂:

  V₂ = P₁V₁ T₂ / (P₂ T₁)

Substitute and compuite:

V₂ = P₁V₁ T₂ / (P₂ T₁)

V₂ = 98.7 KPa × 10.0 L × 293.15 K / (102.7 KPa × 298.15 K)

V₂ =  9.4 liter ← answer

You can learn more about gas law problems reading this other answer on

Explanation:

7 0
2 years ago
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