All categories

3 years ago

You have 0.14 moles of sodium chloride (NaCl). How many grams do you have? ( 1 mole of NaCl = 58 grams NaCl) *

Chemistry

1 answer:

Step2247 [10]3 years ago

4 0

Answer:

Option D is correct = 8.12 grams of NaCl

Explanation:

Given data:

Moles of sodium chloride = 0.14 mol

Mass of sodium chloride = ?

Solution:

Formula:

Number of moles = mass of NaCl / Molar mass of NaCl

Molar mass of NaCl = 58 g/mol

Now we will put the values in formula.

0.14 mol = Mass of NaCl / 58 g/mol

Mass of NaCl = 0.14 mol × 58 g/mol

Mass of NaCl = 8.12 g of NaCl

Thus, 0.14 moles of NaCl contain 8.12 g of NaCl.

You might be interested in

most radioactive atoms “spontaneously” decay to a more stable form. where does the “additional” energy go once the atoms have de

blsea [12.9K]

When most radioactive atoms “spontaneously” decay to a more stable form the “additional” energy is converted to radiation with the emission of radioactive particles.

<h3>What is radioactivity?</h3>

Radioactivity is the spontaneous decay of the nucleus of an atom with the emission of radiation and nuclear particles.

Elements that spontaneously decay are called radioactive elements.

When these radioactive elements decay, they form more stable isotopes or elements.

The spontaneous decay of atoms of radioactive elements is in order for the nucleus of the atom to become stable and non-radioactive.

Learn more about radioactivity at:

brainly.com/question/26626062

#SPJ1

4 0

1 year ago

At a certain temperature Kc = 9.0 for the equilibrium 24() ⇔ 22(). What is

Iteru [2.4K]

Answer:

Explanation:

5 0

4 years ago

¿Cuántos moles de C3H8 contienen 9.25 x 10^24 moléculas?

Igoryamba

Answer:

$\large \boxed{\text{e. 15.4 mol C$_{3}$H}_{8}}$

Explanation: $\text{Moles of propane} = 9.25 \times 10^{24}\text{ molecules} \times \dfrac{\text{1 mol }}{6.022 \times\ 10^{23} \text{molecules}} = \textbf{15.4 mol}$

5 0

3 years ago

If 60. liters of hydrogen gas at 546 K is cooled to 273 K at constant pressure, the new volume of the gas would be

Korvikt [17]

Answer:30 L

Explanation:

Initial Volume

Initial Temperature

546

Final Temperature

273

Final Vloume

Sol:-

Since the pressure is constant and the question is asking about temperature and volume, i.e,

⇒

⋅

273

546

⇒

Hence the new volume of the gas is

6 0

3 years ago

Calculate the electrical energy per gram of anode material for the following reaction at 298 K:

solmaris [256]

43.8 kJ

<h3>Explanation</h3>

There are two electrodes in a voltaic cell. Which one is the anode?

The lithium atom used to have no oxygen atoms when it was on the reactant side. It gains two oxygen atoms after the reaction. It has gained more oxygen atoms than the manganese atom. Gaining oxygen is oxidation. As a result, lithium is being oxidized.

Oxidation takes place at the anode of a cell. Therefore, the anode of this cell is made of lithium.

Lithium has an atomic mass of 6.94. Each gram of Li would contain 1/6.94 = 0.144 moles of Li atoms. Each Li atom loses one electron in this cell. Therefore, the number of electron transferred, <em>n</em>, equals 0.144 moles for each gram of the anode.

Let $w_\text{max}$ represents the electrical energy produced.

$w_\text{max} = n \cdot F \cdot E_\text{cell}$ , where

<em>n</em> is the <em>number of moles</em> electrons transferred,
<em>F</em> is the Faraday's constant,
<em>E</em> $_\text{cell}$ is the cell potential,

<em>n </em>= 0.144 mol, as shown above, and

<em>F </em>= 96.486 kJ / ( $\text{V} \cdot \text{mol} \; \text{e}^{-}$ ).

Therefore,

$w_\text{max} = n \cdot F \cdot E\\\phantom{w_\text{max}} = 0.144 \times 96.486 \times 3.15 \\\phantom{w_\text{max}} = 43.8 \; \text{kJ}$ .

3 0

3 years ago