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3 years ago

Water temperature is general cooler where?

1 answer:

7 0

The temperature of water is cooler in deep oceans. The temperature there goes to 0°C to -3°C below which the water freezes. The water on the surface of the oceans and deep inside it varies because of the difference in energy of the two layers. One of the widest use of cold water is air conditioning. Cold water has a higher density than warm water. Water gets colder with profundity since chilly, salty sea water sinks to the base of the sea beds underneath the less dense hotter water close to the surface.

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A substance in the solid phase state of matter has

ElenaW [278]

Answer:

A variable shape that adapts to fit its container.

8 0

4 years ago

Hydrogen gas and bromine gas react to form hydrogen bromide gas. How much heat (kJ) is released when 155 grams of HBr is formed

VashaNatasha [74]

Answer:

-37.63KJ

Explanation:

First, we write an equation of reaction:

H + Br ——-> HBr

Now we are told that 155g of HBr is formed. We can calculate the number of moles of HBr formed as follows:

We simply divide the mass of the HBr formed by the molar mass of HBr. The molar mass of HBr is 81g/mol

The number of moles of HBr formed is thus 81/155 = 0.52 moles

The amount of heat released is thus 0.52 * (-72) = -37.63KJ

8 0

3 years ago

How to find the mole to mole ratio

Montano1993 [528]

Mass or part divided my molecular mass

6 0

3 years ago

Read 2 more answers

ILL GIVE BRAINLISTS!!!!!!

8_murik_8 [283]

I think A would be the correct answer to this question.

4 0

3 years ago

Read 2 more answers

Carbonic anhydrase of erythrocytes (Mr 30,000) has one of the highest turnover numbers known. It catalyzes the reversible hydrat

Afina-wow [57]

Explanation:

According to the given data, the turnover number can be calculated as follows.

Turnover number = $K_{cat} = \frac{V_{max}}{\text{Concentration of enzyme}}$

$V_{max} = \frac{\text{Moles of CO_{2} hydrolyzed}{second}$

Therefore, moles of $CO_{2}$ hydrolyzed is as follows.

Moles of $CO_{2}$ hydrolyzed = $\frac{Mass of CO_{2}}{Molar mass of CO_{2}}$

= $\frac{0.30}{44}$

= 0.00682 moles

Now, moles of $CO_{2}$ hydolyzed per second is calculated as follows.

Moles of $CO_{2}$ hydolyzed per second = $\frac{0.00682}{60}$

= $1.137 \times 10^{-4} moles/second = V_{max}$

And,

Moles of enzyme = $\frac{Mass}{\text{Molar mass}}$

= $\frac{10.0 \mu g}{30000}$

= $3.33 \times 10^{-10}$ moles

Therefore, the value of $K_{cat}$ is as follows.

$K_{cat} = \frac{1.137 \times 10^{-4} moles}{3.333 \times 10^{-10} moles}$

= $0.3411 \times 10^{6}$ per second

= $0.3411 \times 60 \times 10^{6}$ per minute

= $20.466 \times 10^{6}$ per minute

Thus, we can conclude that the turnover number ( $K_{cat}$ ) of carbonic anhydrase (in units of $min^{-1}$ ) is $20.466 \times 10^{6}$ per minute.

6 0

4 years ago