To solve this problem it is necessary to apply the related concepts to string vibration. This concept shows the fundamental frequency of a string due to speed and length, that is,
Where
v = Velocity
L = Length
Directly if the speed is maintained the frequency is inversely proportional to the Length:
Therefore the relationship between two frequencies can be described as
Our values are given as,
Therefore the second frequency is
The frequency allocation of 329Hz is note E.
Answer: Frictional force
Explanation:
Since the body is moving at constant velocity, this means that the acceleration of the body is zero. Frictional force is a force of opposition which tends to oppose the moving force of an object on a flat surface.
Mathematically, summation of force on the car along the road will be
Fm - Ff = ma
Fm = moving force
Ff = frictional force
m = mass of the body
a = acceleration of the body
Since a = 0, we have;
Fm -Ff = 0
Fm = Ff (which shows that the two forces acting on the body are equal and opposite)
This frictional force will tend to keep the body at equilibrium.
Explanation:
It is given that,
Length of the string, l = 2 m
Mass of the string, 
Hanged mass in the string, 
1. The tension in the string is given by :
T = 1.96 N
2. Velocity of the transverse wave in the string is given by :
m = M/l
v = 28 m/s
Hence, this is the required solution.
Answer:
16.96 W
Explanation:
Power: This can be defined as the rate at which work is done by an object. The S.I unit of power is Watt(W).
From the question,
P = (F×d)/t....................... Equation 1
Where P = power, F = force, d = distance, t = time.
Given: F = 75 N, d = 42 m, t = 3.1 min = 3.1×60 = 186 s
Substitute these values into equation 1
P = (75×42)/186
P = 16.94 W
Hence the average power delivered by the child = 16.96 W
