Your answer is -6 did that answer your question
<h3>No:1</h3>
The object is moving with constant or uniform acceleration and in average speed
<h3>No:-2</h3>
The object is de accelerating
<h3>No:-3</h3>
The object deaccelerated and came to rest so fast.
<h3>No:-4</h3>
The object moves slowly first then accelerated.
<h3>No:-5</h3>
The object accelerated at first so fast then move with constant acceleration then again accelerated .
To solve this problem we will apply the expression of charge per unit of time in a capacitor with a given resistance. Mathematically said expression is given as

Here,
q = Charge
t = Time
R = Resistance
C = Capacitance
When the charge reach its half value it has passed 10ms, then the equation is,




We know that RC is equal to the time constant, then

Therefore the time constant for the process is about 14ms