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NNADVOKAT [17]
3 years ago
13

When a 3.0 kg mass is hung from a vertical massless spring, the spring is stretched 40 cm. What is the spring constant of the sp

ring?
Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0

Answer:

0.74 N/cm

Explanation:

The following data were obtained from the question:

Mass (m) = 3 Kg

Extention (e) = 40 cm

Spring constant (K) =?

Next, we shall determine the force exerted on the spring.

This can be obtained as follow:

Mass (m) = 3 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

F = mg

F = 3 × 9.8

F = 29.4 N

Finally, we shall determine the spring constant of the spring. This can be obtained as follow:

Extention (e) = 40 cm

Force (F) = 29.4 N

Spring constant (K) =?

F = Ke

29.4 = K × 40

Divide both side by 40

K = 29.4 / 40

K = 0.74 N/cm

Therefore, the spring constant of the spring is 0.74 N/cm

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(Part 1 of 3)
Ksju [112]

1) 1.028 m/s^2

We can solve this part by using Newton's second law:

F=ma (1)

where

F is the net force

m is the mass

a is the acceleration

There are two forces acting on the boat:

F_1= 2.90 \cdot 10^3 N forward

F_2 = 1.69\cdot 10^3 N backward

So the net force is

F=2.90\cdot 10^3-1.69\cdot 10^3=1.21\cdot 10^3 N

We know that the mass of the boat is

m = 1177.5 kg

So we can now use eq.(1) to find the acceleration:

a=\frac{F}{m}=\frac{1.21\cdot 10^3}{1177.5}=1.028 m/s^2

2) 161.0 m

We can solve this part by using the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance travelled

u is the initial velocity

t is the time

a is the acceleration

Here we have

u = 0 (the boat starts from rest)

a=1.028 m/s^2

Substituting t = 17.7 s, we find the distance covered:

s=0+\frac{1}{2}(1.028)(17.7)^2=161.0 m

3) 18.2 m/s

The speed of the boat can be found with the following suvat equation

v=u+at

where

v is the final velocity

u is the initial velocity

t is the time

a is the acceleration

In this case we have

u = 0 (the boat starts from rest)

a=1.028 m/s^2

And substituting t = 17.7 s, we find the final velocity:

v=0+(1.028)(17.7)=18.2 m/s

And the speed is just the magnitude of the velocity, so 18.2 m/s.

6 0
4 years ago
Please answer these questions, its for a physics assignment
laiz [17]

A no . answer is velocity of the object. B no.answer is Acceleration of the object. C no.answer is straight line shape and a velocity graph with a horizontal shape D no.answer is curved shape and a velocity graph with a straight shape.

3 0
3 years ago
Suppose the Sun were suddenly to shrink in size but that its mass remained the same. According to the law of conservation of ang
labwork [276]

I think its angular velocity would increase

8 0
4 years ago
What is the speed of light in water?
Fudgin [204]

Answer:

Speed of the light in water= 225,000 km/s

Explanation:

At the speed with which light propagates through a homogeneous and transparent medium, it is a constant characteristic of that medium, and therefore, it changes from one medium to another.

Due to its enormous magnitude, the measurement of the speed of light has required the invention of ingenious procedures that will overcome the inconvenience of short land distances in relation to such extraordinary speed.

Astronomical methods and terrestrial methods have been giving ever closer results. At present, the value c = 299,792,458 km / s is accepted for the speed of light in a vacuum. In any transparent material medium the light propagates with a speed that is always lower than c. Thus, for example, in water it does so at around 75% of the speed of light in a vacuum: about 225,000 km / s.

8 0
3 years ago
Juggles the clown stands on one end of a teeter-totter at rest on the ground. Bangles the clown jumps off a platform 2.4 m above
tester [92]

Answer:

mj = 53.3kg

Explanation:

Since both gravitational energies are the same:

Eb = Ej   =>   mb*g*hb = mj*g*hj

Solving for mj:

mj = mb*hb/hj = 80*2.4/3.6

mj = 53.3kg

5 0
3 years ago
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