Answer:
The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.
Explanation:
Given that,
Amplitude = 0.08190 m
Frequency = 2.29 Hz
Wavelength = 1.87 m
(a). We need to calculate the shortest transverse distance between a maximum and a minimum of the wave
Using formula of distance

Where, d = distance
A = amplitude
Put the value into the formula


Hence, The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.
Answer:38.66 m
Explanation:
Given
launch angle 
launch velocity 
center of mass continue to travel its original Path so it center of mass will be at a distance of



Center of mass will be at 
(b)if one of the piece will be at x=26 m then other will be at




Potential energy is energy stored due to its position. Thermal energy is energy released as heat
Answer:
Depends on what pole it is.
Explanation:
If the poles of the cars and magnets are the same they will repel, if different, attracts.