A gas occupies 900.0 mL at a temperature of 27.0 ˚C. Assuming constant pressure, what is its volume if it is heated to 132.0 ˚C?
1 answer:
Answer:
new volume is 1215mL
Explanation:
using Charles law , the volume of a fixed mass of gas is directly proportional to its temperature provide that pressure is kept constant.
V1=900mL ,
convert the temperatures from Celsius to kelvin temperature.
T1 =27°C =27+273 =300K
T2 =132°C = 132+273=405K
V2= 1215mL
You might be interested in
Answer:
M
Explanation:
Henry's law relational the partial pressure and the concentration of a gas, which is its solubility. So, at the sea level, the total pressure of the air is 1 atm, and the partial pressure of O2 is 0.21 atm. So 21% of the air is O2.
Partial pressure = Henry's constant x molar concentration
0.21 = Hx1.38x
H =
H = 152.17 atm/M
For a pressure of 665 torr, knowing that 1 atm = 760 torr, so 665 tor = 0.875 atm, the ar concentration is the same, so 21% is O2, and the partial pressure of O2 must be:
P = 0.21*0.875 = 0.1837 atm
Then, the molar concentration [O2], will be:
P = Hx[O2]
0.1837 = 152.17x[O2]
[O2] = 0.1837/15.17
[O2] = M