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Artist 52 [7]
3 years ago
10

How many moles are in 20.50 grams of NH3?

Chemistry
2 answers:
Alex777 [14]3 years ago
8 0
A.) <span>3.4 x 10 -24 moles would be your correct Answer.

Hope this helps!</span>
Tema [17]3 years ago
6 0
Sorry, the correct answer is A. 3.4 x 10 - 24

Hope I helped ; )
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Is burning sugar a chemical or physical change? Please provide explanation
solong [7]

Answer:

It is a chemical change

Explanation:

the reason is because the will not be able to materialize back into it's original form.

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If the radius of the sun is 7.01×105 km, what is the volume of the sun in cm3?
vivado [14]

Answer:

1 km * 1000 m / km * 100 cm / m = 10^5 cm / km

V = 4 / 3 pi R^3

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V = 1.443^10^3 * 10^30 = 1.44 10^33cm^3

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3 years ago
Explain why a steel object continues to rust even after its outer layers have corroded.
Aliun [14]

Answer:

Explanation:

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3 years ago
During surgery, a patient receives 3.5 pt of plasma. How many milliliters of plasma were given?
Readme [11.4K]

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1656.116

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4 0
3 years ago
Be sure to answer all parts. The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. H2(g) + CO2(g) ⇌ H2O(g) +
nikklg [1K]

<u>Answer:</u>

<u>For 1:</u> The value of \Delta G for the chemical equation is -24.636 kJ/mol

<u>For 2:</u> The value of \Delta G for the chemical equation is -20.925 kJ/mol

<u>Explanation:</u>

For the given chemical equation:

H_2(g)+CO_2(g)\rightleftharpoons H_2O(g)+CO(g)

  • <u>For 1:</u>

To calculate the \Delta G for given value of equilibrium constant, we use the relation:

\Delta G=-RT\ln K_p      .....(1)

where,

\Delta G = ? kJ/mol

R = Gas constant = 8.314J/K mol

T = temperature = 2000 K

K_p = equilibrium constant in terms of partial pressure = 4.40

Putting values in above equation, we get:

\Delta G=-(8.314J/Kmol)\times 2000K\times \ln (4.40)\\\\\Delta G=-24636.12J/mol

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, -24636.12 J/mol = -24.636 kJ/mol

Hence, the value of \Delta G for the chemical equation is -24.636 kJ/mol

  • <u>For 2:</u>

The expression of K_p for the given chemical equation is:

K_p=\frac{p_{CO}p_{H_2O}}{p_{H_2}p_{CO_2}}

We are given:

p_{CO}=1.18atm\\p_{H_2O}=0.66atm\\p_{CO_2}=0.82atm\\p_{H_2}=0.27atm

Putting values in above equation, we get:

K_p=\frac{1.18\times 0.66}{0.27\times 0.82}\\\\K_p=3.52

Now, calculating the value of \Delta G by using equation 1:

R = Gas constant = 8.314J/K mol

T = temperature = 2000 K

K_p = equilibrium constant in terms of partial pressure = 3.52

Putting values in equation 1, we get:

\Delta G=-(8.314J/Kmol)\times 2000K\times \ln (3.52)\\\\\Delta G=-20925.68J/mol

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, -20925.68 J/mol = -20.925 kJ/mol

Hence, the value of \Delta G for the chemical equation is -20.925 kJ/mol

3 0
3 years ago
Read 2 more answers
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