Consider the following balanced equation for the dissociation of barium hydroxide in an aqueous solution.
-dn.net/?f=%5Csmall%20Ba%28OH%29_%7B2%7D_%7B%28s%29%7D%20%5Crightleftharpoons%20Ba%5E%7B2%2B%7D_%7B%28aq%29%7D%20%2B%202OH%5E%7B-%7D_%7B%28aq%29%7D" id="TexFormula1" title="\small Ba(OH)_{2}_{(s)} \rightleftharpoons Ba^{2+}_{(aq)} + 2OH^{-}_{(aq)}" alt="\small Ba(OH)_{2}_{(s)} \rightleftharpoons Ba^{2+}_{(aq)} + 2OH^{-}_{(aq)}" align="absmiddle" class="latex-formula">
= 5 x 10⁻³A 1M solution of barium nitrate is added to the solution. What is the solubility of barium hydroxide after this addition?a. 0.035Mb. 0.108Mc. 0.050Md. 0.118Me. 0.003M
1 answer:
You might be interested in
Answer:
Equilibrium constant expression for :
.
Where
,
, and
denote the activities of the three species, and
,
, and
denote the concentrations of the three species.
Explanation:
<h3>Equilibrium Constant Expression</h3>The equilibrium constant expression of a (reversible) reaction takes the form a fraction.
Multiply the activity of each product of this reaction to get the numerator. is the only product of this reaction. Besides, its coefficient in the balanced reaction is one. Therefore, the numerator would simply be
.
Similarly, multiply the activity of each reactant of this reaction to obtain the denominator. Note the coefficient "" on the product side of this reaction.
is equivalent to
. The species
appeared twice among the reactants. Therefore, its activity should also appear twice in the denominator:
.
That's where the exponent "" in this equilibrium constant expression came from.
Combine these two parts to obtain the equilibrium constant expression:
.
In dilute solutions, the equilibrium constant expression can be approximated with the concentrations of the aqueous "" species. Note that all the three species here are indeed aqueous. Hence, this equilibrium constant expression can be approximated as:
.
Answer : The chemical formula of pure substances are different from those of mixtures because all the matter that exists on earth can be classified into two categories namely; pure substances and mixtures.
A pure substance always consists of a single element or compound. Example Oxygen is formed only of oxygen (O) atoms; whereas the table salt which is formed only by sodium chloride (NaCl) molecules is a compound which is made up of pure elements. A pure substance cannot be further divided into its components.
A mixture is made up of different compounds and/or elements. It can be easily separated using any physical method. Example, sand, salt and saw dust mixed together as a mixture. Also, it will not have a definite chemical formula.
Please refer the attachment for better understanding.
