Consider the following balanced equation for the dissociation of barium hydroxide in an aqueous solution.
-dn.net/?f=%5Csmall%20Ba%28OH%29_%7B2%7D_%7B%28s%29%7D%20%5Crightleftharpoons%20Ba%5E%7B2%2B%7D_%7B%28aq%29%7D%20%2B%202OH%5E%7B-%7D_%7B%28aq%29%7D" id="TexFormula1" title="\small Ba(OH)_{2}_{(s)} \rightleftharpoons Ba^{2+}_{(aq)} + 2OH^{-}_{(aq)}" alt="\small Ba(OH)_{2}_{(s)} \rightleftharpoons Ba^{2+}_{(aq)} + 2OH^{-}_{(aq)}" align="absmiddle" class="latex-formula">
= 5 x 10⁻³A 1M solution of barium nitrate is added to the solution. What is the solubility of barium hydroxide after this addition?a. 0.035Mb. 0.108Mc. 0.050Md. 0.118Me. 0.003M
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Answer:
4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.
Explanation:
The balanced equation for the reaction between silicon dioxide and carbon at high temperature is given as:
1 mole silicon dioxide reacts with 3 moles of carbon to give 1 moles of silicon carbide and 2 moles of carbon monoxide.
Mass of SiC = 3.00kg = 3000.00 g
1 kg = 1000 g
Molecular mass of SiC = 40 g/mol
Moles of SiC =
According to reaction, 1 mole of SiC is produced from 1 mole of silicon dioxide.
Then 75 moles of SiC will be produce from:
of silicon dioxide.
mass of 75 moles of silicon dioxde:
4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.