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zhenek [66]
3 years ago
15

Which of the following is true about compounds

Chemistry
1 answer:
kobusy [5.1K]3 years ago
5 0

Answer:

Explanation: t

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How many moles are present in 3.4 x 1023 atoms of Na?
Andrej [43]
<h3><u>moles of H2SO4</u></h3>

Avogadro's number (6.022 × 1023) is defined as the number of atoms, molecules, or "units of anything" that are in a mole of that thing. So to find the number of moles in 3.4 x 1023 molecules of H2SO4, divide by 6.022 × 1023 molecules/mole and you get 0.5646 moles but there are only 2 sig figs in the given so we need to round to 2 sig figs. There are 0.56 moles in 3.4 x 1023 molecules of H2SO4

Note the way this works is to make sure the units are going to give us moles. To check, we do division of the units just like we were dividing two fractions:

(molecules of H2SO4) = (molecules of H2SO4)/1 and so we have 3.4 x 1023/6.022 × 1023 [(molecules of H2SO4)/1]/[(molecules of H2SO4)/(moles of H2SO4)]. Now, invert the denominator and multiply:

<h3 />
7 0
2 years ago
In the lab there is a vile of mercury and it has a mass of 43.0 grams. If the density of mercury is 13.6 g/mL, what is the volum
Vitek1552 [10]

Answer:

<h2>The answer is 3.16 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}

From the question

mass = 43 g

density = 13.6 g/mL

The volume is

volume =  \frac{43}{13.6}  \\   = 3.161764

We have the final answer as

<h3>3.16 mL</h3>

Hope this helps you

8 0
3 years ago
Why can water be used in the cooling system of a car? A. it always heats the car in the winter B. it helps fluctuate temperature
JulsSmile [24]
The answer is C. It resists fast temperature change
8 0
3 years ago
Read 2 more answers
A sample of rubidium contains two different isotopes. 72.15% of the sample
Leona [35]

Answer:

Average atomic mass  = 85.557 amu.

Explanation:

Given data:

Percent abundance of Rb-85 = 72.15%

Percent abundance of Rb-87 = 27.85%

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass = (72.15×85)+(27.85×87) /100

Average atomic mass =  6132.75 + 2422.95 / 100

Average atomic mass = 8555.7 / 100

Average atomic mass  = 85.557 amu.

4 0
2 years ago
Science pls helppp?!
hichkok12 [17]

Answer:

2nd one down

Explanation: distance divided by time interval

6 0
2 years ago
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