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AleksAgata [21]
4 years ago
15

You perform 556 J of work lifting a box to a height of 1.3m. How much force did you use to lift the box?

Physics
2 answers:
yuradex [85]4 years ago
5 0

Answer:

The work is given 556 J. Here work is performed horizontally so your distance d=1.3 m

W=F.d

F=W/d =556/1.3 = 427.69 N

Explanation:

babunello [35]4 years ago
4 0
The work is equal to the product between the force applied and the distance covered by the box:
W=Fd
In our problem, W=556 J, and d=1.3 m (the box is lifted to a height of 1.3 m, so it covered 1.3 m from its initial point). Therefore we can find the force applied to lift the box:
F= \frac{W}{d}= \frac{556 J}{1.3 m}=427.7 N
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See Explanation

Explanation:

a) We know that;

v = λf

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Hence;

v = 6.5 m * 0.24 Hz

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b)The amplitude of the wave is;

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c) Since the wave speed does not depend on the amplitude of the wave then the answer in (a) above remains the same

Where d = 0.30 m

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3 years ago
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Answer:

\boxed{v=\frac {V}{\sqrt {2}}}

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We know that frequency of simple pendulum follows that f=\frac {1}{2\pi} \sqrt {\frac {g}{l}}

Now, the speed of the father will be V=Lf= L\times (\frac {1}{2\pi} \sqrt {\frac {g}{l}}) while for the child the speed will be v=\frac {L}{2}\times (\frac {1}{2\pi} \sqrt {\frac {g}{0.5l}})

The ratio of the father’s speed to the child’s speed will be

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Answer:

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s = v * t

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therefore, during this inattentive period, 52.7 m was travelled.

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3 years ago
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