All categories

3 years ago

How many estimates are used in the calculation of depreciation?

2 answers:

8 0

Answer: The correct answer is : There are several methods to calculate depreciation, such as: straight line, activity or units produced, sum of annual digits and double share on the decreasing value.

Explanation: The most commonly used methods are, the linear method, where the original cost of an asset is divided by its estimated useful life to find the amount to be amortized each year and also the accelerated depreciation method is used in which more depreciation is provided the first years of useful life of the asset and for the remaining years a lower depreciation is assigned. This method in turn can be: doubly decreasing balance (200%), 150% decreasing balance, 125% decreasing balance and digits of the sum of the years.

xeze [42]3 years ago

3 0

Answer:

Two estimates

Explanation:

There are mainly two estimates used in the calculation of depreciation such as the useful life and the salvage value of an asset. The salvage value is defined as the predicted amount that will be obtained by a company from an asset when it is disposed at the end of the useful life of the particular asset. On the other hand, the useful life commonly refers to the estimation of how long the asset is useful for the company. This is different from the lifespan of the asset.

You might be interested in

What is the definition of Physics?

pychu [463]

Answer:

This is the simplified definition.

Explanation:

The main goal of physics is to explain how things move in space and time and understand how the universe behaves.

4 0

3 years ago

Read 2 more answers

Suppose the microphone on an AM radio is not working properly. Which best explains how this will affect the process of amplitude

Anna007 [38]

You can have it your own definition of

3 0

3 years ago

Read 2 more answers

3.27 moles of an ideal gas in a 50.0 L tank has a pressure of 171000 Pa. What is the temperature of the gas? (Unit=degrees C)

laiz [17]

The temperature of the gas is 41.3 °C.

Answer:

The temperature of the gas is 41.3 °C.

Explanation:

So on combining the Boyle's and Charles law, we get the ideal law of gas that is PV=nRT. Here P is the pressure, V is the volume, n is the number of moles, R is gas constant and T is the temperature. The SI unit of pressure is atm. So we need to convert 1 Pa to 1 atm, that is 1 Pa = 9.86923× $10^{-6}$ atm. Thus, 171000 Pa = 1.6876 atm.

We know that the gas constant R = 0.0821 atmLMol–¹K-¹. Then the volume of the gas is given as 50 L and moles are given as 3.27 moles.

Then substituting all the values in ideal gas equation ,we get

1.6876×50=3.27×0.0821×T

Temperature = $\frac{84.38}{0.268467} =314.3 K$

So the temperature is obtained to be 314.3 K. As 0°C = 273 K,

Then 314.3 K = 314.3-273 °C=41.3 °C.

Thus, the temperature is 41.3 °C.

3 0

3 years ago

. A stationary mass explodes into two parts of mass 4 kg and 40 kg . If the K.E of larger mass is 100 J . The K.E of small mass

alisha [4.7K]

Answer:

10J

Explanation:

KE = (1/2)mv²

100J = (.5)(40kg)v²

v²=(100J)/(20kg)

v²= 5

KE = 5(.5)(4kg)

KE = 10J

3 0

3 years ago

Julie drives 100 mi to Grandmother's house. On the way to Grandmother's, Julie drives half the distance at 30.0 mph and half the

salantis [7]

Answer:

Explanation:

Given

Distance to grandmother's house=100 mi

it is given that during return trip Julie spend equal time driving with speed 30 mph and 70 mph

Let Julie travel x mi with 30 mph and 100-x with 70 mph

$\frac{x}{30}=\frac{100-x}{70}$

x=30 mi

Therefore

Julie's Average speed on the way to Grandmother's house $=\frac{100}{\frac{50}{30}+\frac{50}{70}}$

=42 mph

On return trip

$=\frac{100}{2\frac{30}{30}}=50 mph$

6 0

3 years ago