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suter [353]
3 years ago
15

How many estimates are used in the calculation of depreciation?

Physics
2 answers:
Kipish [7]3 years ago
8 0

Answer:  The correct answer is :  There are several methods to calculate depreciation, such as: straight line, activity or units produced, sum of annual digits and double share on the decreasing value.

Explanation:  The most commonly used methods are, the linear method, where the original cost of an asset is divided by its estimated useful life to find the amount to be amortized each year and also the accelerated depreciation method is used in which more depreciation is provided the first years of useful life of the asset and for the remaining years a lower depreciation is assigned. This method in turn can be: doubly decreasing balance (200%), 150% decreasing balance, 125% decreasing balance and digits of the sum of the years.

xeze [42]3 years ago
3 0

Answer:

Two estimates

Explanation:

There are mainly two estimates used in the calculation of depreciation such as the useful life and the salvage value of an asset. The salvage value is defined as the predicted amount that will be obtained by a company from an asset when it is disposed at the end of the useful life of the particular asset. On the other hand, the useful life commonly refers to the estimation of how long the asset is useful for the company. This is different from the lifespan of the asset.  

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You are sitting on a deck of your house surrounded by oak trees. You hear the sound of an acorn hitting the deck. You wonder if
Black_prince [1.1K]

Answer: 96N

Explanation:

To calculate the velocity of the impact On the persons head, we have

h = gt²/2

14 = 9.81t²/2

t² = 28/9.8

t² = 2.86

t = 1.69s

V = u + at

V = 0 + 9.81*1.69

V = 16.58m/s

a(average) = (v1² + v2²) /2Δy

a(average) = 16.58² + 0)/2 * 0.005

a(average) = 274.8964/0.01

a(average) = 27489.64m/s²

Using newton's second law of motion,

F(average) = m * a(average)

F(average) = 0.0035 * 27489.64

F(average) = 96.21N

Therefore the force needed by the acorn to do much damage starts from 96N

8 0
2 years ago
Write a hypothesis for Part II of the lab, which is about the relationship described by F = ma. In the lab, you will use a toy c
hoa [83]

Answer:

F=ma is the relationship where, F is force, m is mass and a is acceleration.

Newton's second law states that  the unbalanced force applied to the object accelerates the object which is directly proportional to the force and inversely to the mass.

If we apply force to a toy car then It will accelerate.

This is how Newton's second law of motion is verified.

5 0
3 years ago
Read 2 more answers
A hard drive has 250 gigabytes of storage?
Dafna11 [192]
A. 0.25 terabytes
b. 2.5e + 17
4 0
3 years ago
A curved road has a radius of 120 m and a cant angle of 48 degrees. What is the maximum speed to stay on the curve in the absenc
zalisa [80]

Answer:

Maximum speed, v = 36 m/s                                                          

Explanation:

Given that,

The radius of the curved road, r = 120 m

Road is at an angle of 48 degrees. We need to find the maximum speed of stay on the curve in the absence of friction. On a banked curve, the angle at which it is cant is given by :

tan\theta=\dfrac{v^2}{rg}

g is the acceleration due to gravity  

v=\sqrt{rg\ tan\theta}

v=\sqrt{120\times 9.8\times \ tan(48)}

v = 36.13 m/s

or

v = 36 m/s

So, the maximum speed to stay on the curve in the absence of friction is 36 m/s. Hence, this is the required solution.

7 0
3 years ago
What is the force on a body if the mass of the body is 2300g? (acceleration due to = 9.8ms-1) ​
amm1812

Hello jamaicandoll!

\huge \boxed{\mathfrak{Question} \downarrow}

What is the force on a body if the mass of the body is 2300g? (acceleration due to gravity = - 9.8m/s²) .

\huge \boxed{\mathfrak{Answer} \downarrow}

Given,

  • Mass (m) = 2300 g = 2.3 kg
  • Acceleration (a) = -9.8 m/s²
  • Force (F) = ?

We know that, force = mass × acceleration.

So,

F = ma

F = 2.3 × -9.8

F = \boxed{\underline{\bf \: -22.54\:N}}

__________________

Hope it'll help you!

ℓu¢αzz ッ

5 0
2 years ago
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