what is the best term to describe information sent as patterns and codes in the controlled flow of electrons through a circuit

Fill in the blank please I’m very confused

Reika [66]

For the third one on the top you can put to get solar panels on your roof

4 0

3 years ago

The purpose of a cell (battery) is to: Question 2 options: store chemical energy and transfer it to thermal energy when a circui

xz_007 [3.2K]

Answer:

Store chemical energy and transfer it to electrical energy when a circuit is connected.

Explanation:

A battery (single cell) is a container made of one cell that can produce a particular amount of electrical energy when needed.

It works by converting chemical energy to electric energy which is then used as a power source.

It stores up chemical energy and when connected to an external circuit, it provides electrical energy (through the flow of electrical current) to the circuit.

A battery is usually made up of a positive electrode and a negative electrode.

6 0

3 years ago

What important discovery was made by edmond halley and alexis clairaut, using newton's ideas of mathematics and gravity?

Semmy [17]

They were able to find the orbit of a comet and predict the year of its return.

8 0

3 years ago

Read 2 more answers

A fan is to accelerate quiescent air to a velocity of 8 m/s at a rate of 9 m3 /s. determine the minimum power that must be suppl

ELEN [110]

Given:
ρ = 1.18 kg/m³, density of air
v = 8 m/s, flow velocity
Q = 9 m³/s, volumetric flow rate

The minimum power required (at 100% efficiency) is
$\frac{1}{2} (8 \, \frac{m}{s} )^{2}*(9 \, \frac{m^{3}}{s} )*(1.18 \, \frac{kg}{m^{3}}) = 339.84 \, W$

The actual power will be higher because 100% efficiency is not possible.

Answer: 339.8 W (nearest tenth)

8 0

4 years ago

Physics question, please answer this ASAP, thanks!

miv72 [106K]

(a) The gravitational force received by each 1 kg mass is 8.66 N.

(b) The magnitude of gravitational acceleration is 8.66 m/s².

(c) The orbital speed of the ISS is 7,663.6 m/s.

(d) The time take for the ISS to orbit round the Earth is 5,558.75 s = 1.54 hours.

<h3>Gravitational force received by each 1 kg mass</h3>

The gravitational force received by each 1 kg mass is calculated as follows;

F = Gm₁m₂/r²

where;

m₁ is mass of Earth
m₂ is mass of ISS
r is the distance between the ISS and center of Earth

F = (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ x 1) / (6780,000)²

F = 8.66 N

<h3>Magnitude of gravitational acceleration</h3>

mg = GMm/r²

g = GM/r²

where;

M is mass of Earth

g = (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ ) / (6780,000)²

g = 8.66 m/s²

<h3>Orbital Speed of the ISS</h3>

v = √GM/r

v = √(6.67 x 10⁻¹¹ x 5.97 x 10²⁴ / 6780,000)

v = 7,663.6 m/s

<h3>Time of motion of the ISS round the Earth</h3>

T = 2πr/v

T = (2π x 6780,000) / (7663.6)

T = 5,558.75 seconds

1 hour = 3600 seconds

= 5,558.75/3600

= 1.54 hours

Thus, the gravitational force received by each 1 kg mass is 8.66 N.

The magnitude of gravitational acceleration is 8.66 m/s².

The orbital speed of the ISS is 7,663.6 m/s.

The time take for the ISS to orbit round the Earth is 5,558.75 s = 1.54 hours.

Learn more about orbital speed here: brainly.com/question/22247460

#SPJ1

4 0

2 years ago