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Lerok [7]
3 years ago
14

Round off each measurement to the number of significant figures shown in parentheses.

Chemistry
1 answer:
Wewaii [24]3 years ago
6 0

We have to round off each measurement to the number of significant figures.

The correct answers are: 265.9, 0.00045 and 65 respectively.

265.991 when expressed in 4 significant figure it rounds off as 265.9 because  265.9 represents the value 265.991.

0.0004513 when expressed in 2 significant figure it rounds off as 0.00045 because zero before and after decimal are not significant.

6593 when expressed in 2 significant figure it rounds off as 65.


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A 50.0g g sample of 16n decays to 12.5g in 14.4 seconds. What is its half life
mixas84 [53]
T is amount after time t 
<span>Ao is initial amount </span>
<span>t is time </span>
<span>HL is half life </span>

<span>log (At) = log [ Ao x (1/2)^(t/HL) ] </span>
<span>log (At) = log Ao + log (1/2)^(t/HL) </span>
<span>log (At) = log Ao + (t/HL) x log (1/2) </span>

<span>( log At - log Ao) / log (1/2) = t / HL </span>
<span>log (At/Ao) / log (1/2) = t / HL </span>

<span>HL = t / [( log (At / Ao)) / log (1/2) ] </span>

<span>HL = 14.4 s / [ ( log (12.5 / 50) / log (1/2) ] </span>

<span>HL = 14.4 s / 2 = 7.2 seconds </span>
8 0
3 years ago
Which of the following is the best explanation for the fact that crushing increases the rate at which a solid dissolves in a liq
Oksana_A [137]
It’s D cause i know I know I know I know
7 0
3 years ago
A monoprotic weak acid, HA , dissociates in water according to the reaction HA(aq)↽−−⇀H+(aq)+A−(aq) The equilibrium concentratio
Pachacha [2.7K]

Answer:

pK_{a} of HA is 6.80

Explanation:

pK_{a}=-logK_{a}

Acid dissociation constant (K_{a}) of HA is represented as-

                K_{a}=\frac{[H^{+}][A^{-}]}{[HA]}

Where species inside third bracket represents equilibrium concentrations

Now, plug in all the given equilibrium concentration into above equation-

K_{a}=\frac{(2.00\times 10^{-4})\times (2.00\times 10^{-4})}{0.250}

So, K_{a}=1.6\times 10^{-7}

Hence pK_{a}=-log(1.6\times 10^{-7})=6.80

6 0
3 years ago
Which is the correct set of products for the acid-base neutralization reaction between hydrochloric acid and sodium hydroxide?
nydimaria [60]

Answer: I think the answer is C. NaCl and H2O

Explanation: I’m not sure tho

3 0
2 years ago
Which statements about the structure of the periodic table are true?
Liono4ka [1.6K]

Answer:

Below are the statements which are true about the structure of the periodic table:

B: The inner transition elements are placed at the bottom of the periodic table for easy viewing.

D: The distribution of electrons in energy levels is responsible for the shape of the periodic table.

Explanation:

Point A:

As we know that in a periodic table there are 7 period s and 18 groups. So, the number of periods is evidently lesser than the number of groups. But the shape of periodic table is regular and rectangular so point A is false.

Point B:

The inner transition elements or -f block elements are put at the bottom for easy viewing. These are the elements that have the valence electrons only  in the f-orbital's. Therefore, they are placed separately at the bottom side of the table so that they can be easily viewed or studied from there. So, point B is true.

Point C:

If we talk about option C, then it is very clear and true that considering a rectangular shape of the periodic table, the groups are vertically arranged and periods are horizontally arranged, therefore it is false.

Point D:

Atoms of all elements have definite electronic distribution in different energy levels like s, p d or f. This is a very prominent feature of periodic tale that elements are divided in specific blocks, s, p, d and f based on their electronic configurations. Therefore, it is true.

Point E:

We also know that no. of metals in a periodic table are more than the no. of non metals like almost 91 out of 118 elements  are metals in periodic table. Therefore, the point E "Nonmetals take up more than half the area of the periodic table." is false.

Hope it helps!

5 0
3 years ago
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