Answer:
8.25 g HNO3 (please correct me if I'm wrong!)
2C2H2 + 5O2 ---> 4CO2 + 2H2O
<span>mole ratio of O2:C2H2 is 2.5:1 </span>
<span>for 37 mol C2H2 you need 2.5 x 37 mol = 92.5 moles O2. </span>
<span>Thus, O2 is limiting.</span>
From the given balanced equation we have find out the amount (in gm) of Ag formed from 5.50 gm of Ag₂O.
2Ag₂O(s) → 4Ag (s) + O₂ (g)
We know, molecular mass of Ag₂O= 231.7 g/mol, and atomic mass of Ag= 107.8 g/mol. Given, mass of Ag₂O=5.50 gm. Number moles of Ag₂O=
= 0.0237 moles.
From the balanced chemical reaction we get 2 (two) moles of Ag₂O produces 4 (four) moles of Ag. So, 0.0237 moles of Ag₂O produces
moles=0.0474 moles of Ag= 0.0474 X 107.8 g of Ag=5.11g Ag.
Therefore, 5.50 g Ag₂O produces 5.11 g of Ag as per the given balanced chemical reaction.