A bicycle and a rider with a combined mass of 110 kilograms are traveling at a speed of 8 meters per second. What is the kinetic
energy of the bicycle and the rider?
KE= 1/2 mv2
KE= 1/2 mv2
1 answer:
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Answer:
320 N/m
Explanation:
From Hooke's law, we deduce that
F=kx where F is applied force, k is spring constant and x is extension or compression of spring
Making k the subject of formula then
Conversion
1m equals to 100cm
Xm equals 25 cm
25/100=0.25 m
Substituting 80 N for F and 0.25m for x then
Therefore, the spring constant is equal to 320 N/m
Answer:
A.
B. rev=10.79rev
Explanation:
A.
500rpm
the time is about 2.60s knowing the acceleration is:
so:
B.
The CD stop so the final velocity is vf=0 so:
Total revolutions: