Answer:
Relative to Sir George's starting point, the knights collide at a distance of 38.43 m from Sir George's starting point.
Explanation:
Let the distance covered by Sir George be  
 
and the distance covered by Sir Alfred be 
Since the knights collide, hence they must have traveled for the same amount of time just before collision
From one of the equations of motion for linear motion 

Where  is the distance traveled
 is the distance traveled
 is the initial velocity
 is the initial velocity
 is the acceleration
 is the acceleration
and  is the time
 is the time
For Sir George, 

 = 0 m/s (Since they start from rest)
 = 0 m/s (Since they start from rest)
 0.21 m/s²
0.21 m/s²
Hence, 
 becomes
 becomes


Now, for Sir Alfred

 = 0 m/s (Since they start from rest)
 = 0 m/s (Since they start from rest)
 0.26 m/s²
0.26 m/s²
Hence, 
 becomes
 becomes


Since, they traveled for the same time,  just before collision, we can write
 just before collision, we can write

Since, the two nights are 86 m apart, that is, the sum of the distances covered by the knights just before collision is 86 m. Then we can write that 
 m
 m
Then, 
Then, 
 becomes
 becomes 


 m
 m
∴ Sir George covered a distance of 38.43 m just before collision.
Hence, relative to Sir George's starting point, the knights collide at a distance of 38.43 m from Sir George's starting point.