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Furkat [3]
3 years ago
9

A researcher wants to test the solubility (property of being dissolved) of salt in water as the temperature of the water increas

es.
Design an experiment to test his hypothesis that as the water temperature increases the solubility of the salt in water also increases. Include the following in your experimental design: experimental setup, procedure for data collection methods and criteria for evaluating the hypothesis.



Materials: salt, water, beakers, heat source, thermometer, balance
Chemistry
1 answer:
aev [14]3 years ago
6 0
Have about 5 beakers all with different temperatures of water. Put in a teaspoon of salt at a time and when it stops dissolving stop adding and record how much salt it took. It should be more salt as the temperature rises. The independent variable is the waters temperature. The dependent variable is how much salt is used. Make sure that there is the same amount of water in each beaker. Or else it won’t work.
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What happens when the vapor pressure of a liquid is equal to the external pressure? The liquid freezes The intermolecular forces
Makovka662 [10]

Answer:

The liquid boils.

Explanation:

Vapor pressure is simply defined as the pressure exerted on a substance (solid/liquid) by the vapor of the substance collected just at the top of the surface of the substance. In concise words, it is the pressure of Vapor that is in contact with its solid or liquid state.

For a liquid, it is the pressure of the Vapor gathering at the top of the surface of the liquid.

When this Vapor pressure matches the external pressure, the temperature stays constant and the molecules of the liquid all through the liquid can gain enough energy, rise to the surface of the liquid and break free in gaseous form; thereby, boiling.

The definition of boiling point basically explains that it is the point at which temperature stays constant, and the vapour pressure of the liquid matches the atmospheric/external pressure around the liquid and its liquid molecules change into vapor.

This is why liquids boil faster at higher altitudes; the atmospheric pressure at higher altitudes is reduced, hence, the temperature at which liquid boils at this high altitude is normally lower than its known boiling point temperature.

It is also why food cooks to a temperature higher than the boiling point of water in a pressure cooker/pot. The added pressure ensures that the cooking water boils at temperatures higher than its boiling point; thereby exposing the cooking ingredients to a higher temperature, leading to faster cooking.

Hence, it is obvious why boiling is the answer to this question.

6 0
3 years ago
What is the photo above showing​
tangare [24]
Carbon? i am confused, if you're asking for the element or what is happening, i need a bit of clarification!
7 0
3 years ago
Study the chemical reaction below and answer the questions that follow: 8Al + 3Fe₃O₄ → 4Al₂O₃ + 9Fe How many moles of iron would
julia-pushkina [17]

Answer: the answewr is A. hope this helps!

Explanation:

3 0
3 years ago
suppose that two hydroxides, moh and m′ (oh)2, both have a ksp of 1.39 × 10−12 and that initially both cations are present in a
11Alexandr11 [23.1K]

When base is added in order to increase the pH of a solution, it results in MOH salt <u>precipitating first.</u>

Equation :

MOH (s)  ⇄ M⁺ (aq)  ₊ OH⁻(aq)

Ksp = [M⁺] [OH⁻]

Ksp = 1.39×10⁻¹² and [M⁺] = 0.001M

∴ 1.39×10⁻¹² = (0.001M) [OH⁻]

[OH⁻] =  1.004×10⁻¹⁹M

pOH = -log [OH⁻] =  11.9

pH = 14 - pOH

= 14 - 11.9

<u>pH = 2.1</u>

To learn more about solubility equilibrium ;

https://brainly.in/question/9213521

#SPJ4

8 0
2 years ago
An aqueous solution of acetic acid is found to have the following equilibrium concentrations at 25 C:
yarga [219]

Answer: 1.79 x 10^-5

Explanation: The equilibrium constant of a reaction can be calculated from the quotient of the concentrations of the products over the concentrations of the reactants, with each termed raised to their respective stoichometric coefficients.

For acetic acid, this equilibrium expression is:

Kc=\frac{[H+] [CH3COO-]}{[CH3COOH]}

Replacing the equilibrium concentrations given by the exercise into the expression above, the equilibrium constant, Kc will be obtained and it is found to be equal to 1.79 x 10^-5.

8 0
3 years ago
Read 2 more answers
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