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Maurinko [17]
3 years ago
11

What is the atom inventory for the following equation after it is properly balanced? ____NaOH + ____CuCl2 Imported Asset ____NaC

l + ____Cu(OH)2 Reactants: Na = 1, O = 1, H = 1, Cu = 2, Cl = 2; Products: Na = 1, O = 1, H = 1, Cu = 2, Cl = 2 Reactants: Na = 1, O = 2, H = 2, Cu= 2, Cl= 2; Products: Na = 1, Cl = 1, Cu = 2, O = 2, H = 2 Reactants: Na = 1, O = 1, H = 1, Cu = 1, Cl = 21; Products: Na = 1, O = 1, H = 1, Cu = 1, Cl = 2 Reactants: Na = 2, O = 2, H = 2, Cu = 1, Cl = 2; Products: Na = 2, Cl = 2, Cu = 1, O = 2, H = 2
Chemistry
1 answer:
faltersainse [42]3 years ago
4 0

Answer:

Reactants: Na = 2, O = 2, H = 2, Cu = 1, Cl = 2;

Products: Na = 2, Cl = 2, Cu = 1, O = 2, H = 2

Explanation:

NaOH + CuCL2 —> NaCl + Cu(OH)2

The balanced equation can be achieved by doing the following:

There are 2 oxygen and 2 hydrogen atom on the right side. This is balanced by putting 2 in front of NaOH as shown below:

2NaOH + CuCL2 —> NaCl + Cu(OH)2

This makes Na to be unbalanced. Now to balance Na, put 2 in front of NaCl as illustrated below

2NaOH + CuCL2 —> 2NaCl + Cu(OH)2

Now the equation is balanced.

Reactants: Na = 2, O = 2, H = 2, Cu = 1, Cl = 2

Products: Na = 2, Cl = 2, Cu = 1, O = 2, H = 2

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Bath salts are typically composed of the ingredients listed below. Identify each item as being acidic, basic, or neutral when di
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Answer:

NaCl neutral

Na₂SO₄ basic

NaHCO₃ basic

K₃PO₄ basic

Na₃C₆H₅O₇ basic

CaCl₂ neutral

Sodium oxalate (Na₂C₂O₄) dissolves and dissociates in water.

Oxalic acid (C₂H₂O₄) dissolves and dissociates in water

Explanation:

<em>Identify each item as being acidic, basic, or neutral when dissolved in water. If a particular ingredient does make an acidic or basic solution, describe how this occurs.</em>

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NaCl

When NaCl is dissolved in water the resulting solution is neutral.

Na₂SO₄

When Na₂SO₄ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the SO₄²⁻ ion.

SO₄²⁻(aq) + H₂O(l) ⇄ HSO₄⁻(aq) + OH⁻(aq)

NaHCO₃

When NaHCO₃ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the HCO₃⁻ ion.

HCO₃⁻(aq) + H₂O(l) ⇄ H₂CO₃(aq) + OH⁻(aq)

K₃PO₄

When K₃PO₄ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the PO₄³⁻ ion.

PO₄³⁻(aq) + H₂O(l) ⇄ HPO₄²⁻(aq) + OH⁻(aq)

Na₃C₆H₅O₇ (sodium citrate)

When Na₃C₆H₅O₇ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the C₆H₅O₇³⁻ ion.

C₆H₅O₇³⁻(aq) + H₂O(l) ⇄ C₆H₆O₇²⁻(aq) + OH⁻(aq)

CaCl₂

When CaCl₂ is dissolved in water the resulting solution is neutral.

Sodium oxalate (Na₂C₂O₄) dissolves and dissociates in water according to the following equation:

Na₂C₂O₄(aq) ⇄ 2 Na⁺(aq) + C₂O₄²⁻(aq)

Oxalic acid (C₂H₂O₄) dissolves and dissociates in water according to the following equation:

C₂H₂O₄(aq) ⇄ C₂HO₄⁻(aq) + H⁺(aq)

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Many people in South America are subsistence farmers. Subsistence farming is...
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growing only enough crops for food to fed the family

Explanation:

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A perfect cube of aluminum metal was found to weigh 20.00 g. The density of aluminum is 2.7 g/ml. What are the dimensions of the
denis23 [38]

Answer:

             Height  = 1.9493 cm

             Width =  1.9493 cm

             Depth  =  1.9493 cm

Solution:

Data Given:

                  Mass  =  20 g

                  Density  =  2.7 g/mL

Step 1: Calculate the Volume,

As,

                                        Density  =  Mass ÷ Volume

Or,

                                        Volume  =  Mass ÷ Density

Putting values,

                                        Volume  =  20 g ÷ 2.7 g/mL

                                        Volume  =  7.407 mL or 7.407 cm³

Step 2: Calculate Dimensions of the Cube:

As we know,

                                        Volume  =  length × width × depth

So, we will take the cube root of 7.407 cm³ which is 1.9493 cm.

Hence,

                                        Volume  =  1.9493 cm × 1.9493 cm × 1.9493 cm

                                        Volume  =  7.407 cm³

4 0
3 years ago
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