Answer:
Molecularity of the rate determining step = 2
Explanation:
Step 1 (slow): H₂O₂ + I⁻ -----> H₂O + OI⁻
Step 2 (fast): H₂O₂ + OI⁻ -----> H₂O + O₂ + I⁻
The rate determining step in a reaction mechanism is also considered as slowest step.
Slowest step is also considered its highest activation energy in energy profile diagram.
In this case intermediate (IO⁻) is formed.
Step 1 considered as a slowest step.
So, Rate = K [H₂O₂][I⁻]
Molecularity = 2
The mass of pentane the student should weigh out is
The density of pentane is 0.626 gcm-3
To calculate the mass of pentane following expression is used,
(Density is defined as the mass divide by volume)
Density = mass / volume
mass of pentane = Density of pentane * Volume of pentane
mass of pentane = 0.626 gcm-3 * 45.0 mL
= 28.17 g
Here the unit of mass of pentane is g,
However the unit of density is gcm-3 and unit of volume is mL i.e. cm3
Hence, Mass = gcm-3 * cm3
Mass = g
The mass of pentane the student should weigh out is 28.17g
Learn more about Density on
brainly.com/question/1354972
#SPJ1
1.
- The changing of liquid to a gas.
2.
- The major source of pollution.
3.
- Carbon dioxide and water vapor trapping heat given off by Earth.
4.
- Layer absorbing ultraviolet rays.
5.
- The changing of a gas to a liquid.
6.
- Layer responsible for reflecting radio waves.
7.
- The layer in which weather changes.

<span>Determine the root-mean-square sped of CO2 molecules that have an average Kinetic Energy of 4.21x10^-21 J per molecule. Write your answer to 3 sig figs.
</span><span>
E = 1/2 m v^2
If you substitute into this formula, you will get out the root-mean-square speed.
If energy is Joules, the mass should be in kg, and the speed will be in m/s.
1 mol of CO2 is 44.0 g, or 4.40 x 10^1 g or 4.40 x 10^-2 kg.
If you divide this by Avagadro's constant, you will get the average mass of a CO2 molecule.
4.40 x 10^-2 kg / 6.02 x 10^23 = 7.31 x 10^-26 kg
So, if E = 1/2 mv^2
</span>v^2 = 2E/m = 2 (4.21x10^-21 J)/7.31 x 10^-26 kg = 115184.68
Take the square root of that, and you get the answer 339 m/s.