Answer:
Therefore,
The resistor value , R is 9.4 kΩ.
Explanation:
Given:
A neon gas tube has
Von = 60.0 V and
Voff = 30.0 V
Capacitor, C = 20.0 μF
Battery , E = 120 V
Frequency = f = 30 hz
To Find:
Resistor , R =?
Solution:
Time period of the wave will be only the charging time of the capacitor,the capacitor will be charged to Von from initial voltage Voff is given by,
Where,
R = Resistance
C =Capacitance
E = Battery in volts
ln = natural Log (Sign)
Substituting the values we get
Therefore,
The resistor value , R is 9.4 kΩ.
Answer:
You will do twice the work of climbing 1 stair.
Explanation:
To obtain the answer to the question, we shall determine the work done on each case. This is illustrated below:
Case 1 ( climbing 2 stairs):
Mass (m) = m
One stair = 4 m
Height (h) = 2 × 4 = 8 m
Acceleration due to gravity (g) = 10 m/s²
Workdone 1 (Wd₁) =?
Wd₁ = mgh
Wd₁ = m × 10 × 8
Wd₁ = 80 × m
Case 2 (Climbing 1 stair)
Mass (m) = m
Height (h) = 4 m
Acceleration due to gravity (g) = 10 m/s²
Workdone 2 (Wd₂) =?
Wd₂ = mgh
Wd₂ = m × 10 × 4
Wd₂ = 40 × m
Now comparing the Workdone in both case:
Workdone 1 (Wd₁) = 80 × m
Workdone 2 (Wd₂) = 40 × m
Wd₁ / Wd₂ = 80 × m / 40 × m
Wd₁ / Wd₂ = 2
Cross multiply
Wd₁ = 2 × Wd₂
Thus, we can see that the Workdone in climbing 2 stairs is twice the Workdone in climbing 1 stair.
Therefore, you will do twice the work of climbing 1 stair.
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Answer:
the ball rebounds 8 times before losing 90% of its energy
Explanation:
given information:
height, h₁ = 1.6 m
rebound height, h₂ = 1.2 m
energy loss = 90% = 0.9
first we can calculate the loss energy after the rebound
energy loss = 1 - [(height of rebound/height of the ball)^n
where
n = number of the bounce
energy loss = 1 - (h₂/h₁)^n
0.9 = 1 - (1.2/1.6)^n
(0.75)^n = 1 - 0.9
n log 0.75 = log 0.1
n = log 0.1/log 0.75
= 8 bounces
<span>You can follow the flow of energy in an ecosystem by following its food Chain or food web.
In short, Answers are:
1- Chain
2- Web
Hope this helps!</span>