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juin [17]
3 years ago
12

During a hard stop, a car and its passengers slow down with an acceleration of 8,0m/s^2. What magnitude force does a 50-kg passe

nger exert on the seat belt in such a stop?
Physics
1 answer:
arlik [135]3 years ago
7 0

Answer:

F = 400 N

Explanation:

Given,

The acceleration of the car, a = 8 m/s²

The mass of the passenger, m = 50 Kg

The force acting on a body is equal to the product of the mass and its acceleration

                                    F = m x a   newtons

Substituting the given values in the above equation,

                                     F = 50 Kg x 8 m/s²

                                        = 400 N

Hence, the force exerted by the person on the seat belt is, F = 400 N

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Allushta [10]

red hot is hot, but other colours are even hotter. stars may be hotter than red hot.

there is also something calle the red shift.

3 0
3 years ago
You have a battery marked " 6.00 V 6.00 V ." When you draw a current of 0.383 A 0.383 A from it, the potential difference betwee
Archy [21]

Answer:

V = 4.81 V

Explanation:

  • As the potential difference between the battery terminals, is less than the rated value of the battery, this means that there is some loss in the internal resistance of the battery.
  • We can calculate this loss, applying Ohm's law to the internal resistance, as follows:

        V_{rint} = I* r_{int}

  • The value of the potential difference between the terminals of the battery, is just the voltage of the battery, minus the loss in the internal resistance, as follows:

       V = V_{b} - V_{rint}  = 5.03 V = 6.0 V - 0.383 A* r_{int}

  • We can solve for rint, as follows:

         r_{int} = \frac{V_{b}-V}{I} =\frac{6.0V-5.03V}{0.383A} = 2.53 \Omega

  • When the circuit draws from battery a current I of 0.469A, we can find the potential difference between the terminals of the battery, as follows:

       V = V_{b} - V_{rint}  = 6.0 V - 0.469 A* 2.53 \Omega= 6.0 V - 1.19 V = 4.81 V

  • As the current draw is larger, the loss in the internal resistance will be larger too, so the potential difference between the terminals of the battery will be lower.
5 0
3 years ago
A wheelbarrow can be used to help lift a load, such as a pile of dirt, and then push the load across a distance. A man pushes a
skelet666 [1.2K]

Answer:

B.) a wheel and axle and a lever

Explanation:

P.S - The exact question is -

Given - A wheelbarrow can be used to help lift a load, such as a pile of dirt, and then push the load across a distance. A man pushes a wheelbarrow.

To find - Which simple machines make up a wheelbarrow?

A.) a pulley and an inclined plane

B.) a wheel and axle and a lever

C.) a pulley and a wheel and axle

D.) a lever and a wedge

Proof -

The correct option is - B.) a wheel and axle and a lever

Wheelbarrows are used to carry more goods from place to place by using minimal force as compared when goods are carried by hand.

With this machine, During hauling people can save time.

4 0
3 years ago
Read 2 more answers
1. What happens to an atom when it gains electrons? *
Deffense [45]

Answer: An atom that gains or loses an electron becomes an ion. If it gains a negative electron, it becomes a negative ion. If it loses an electron it becomes a positive ion

3 0
3 years ago
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An ice skater has a moment of inertia of 5.0 kg · m2when her arms are outstretched, and at this time she is spinning at 3.0 rev/
KatRina [158]

Answer:

Explanation:

Given

Initial Moment of Inertia I_1=5 kg-m^2

initial Spin N_1=3 rev/s

\omega _1=2\pi N_1=2\pi 3=6\pi rad/s

Final Moment Moment of Inertia I_2=2 kg-m^2

Conserving Angular momentum

L_1=L_2

I_1\omega _1=I_2\omega _2

5\times 6\pi=2\times \omega _2

\omega _2=15\pi rad/s

N_2=\frac{\omega _2}{2\pi }

N_2=\frac{15\pi }{2\pi}=7.5 rev/s

8 0
4 years ago
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