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3 years ago

Help with the LAB answers

Chemistry

2 answers:

galben [10]3 years ago

5 0

Answer : The reaction rate at $3^oC,24^oC,40^oC\text{ and }65^oC$ are $36mg/L/sec,142mg/L/sec,190mg/L/sec\text{ and }352mg/L/sec$

Solution : Given,

Mass of tablet = 1000 mg

Volume of water = 0.200 L

Formula used :

$\text{Reaction rate}=\frac{\text{Mass of tablet}/\text{Volume of water}}{\text{Reaction time}}$

Now we have to calculate the reaction rate at different temperatures and reaction time.

$\text{Reaction rate at }3^oC=\frac{1000mg/0.200L}{138.5sec}=\frac{5000mg/L}{138.5sec}=36mg/L/sec$

$\text{Reaction rate at }24^oC=\frac{1000mg/0.200L}{34.2sec}=\frac{5000mg/L}{34.2sec}=142mg/L/sec$

$\text{Reaction rate at }40^oC=\frac{1000mg/0.200L}{26.3sec}=\frac{5000mg/L}{26.3sec}=190mg/L/sec$

$\text{Reaction rate at }65^oC=\frac{1000mg/0.200L}{14.2sec}=\frac{5000mg/L}{14.2sec}=352mg/L/sec$

Therefore, the reaction rate at $3^oC,24^oC,40^oC\text{ and }65^oC$ are $36mg/L/sec,142mg/L/sec,190mg/L/sec\text{ and }352mg/L/sec$

Kaylis [27]3 years ago

5 0

Answer:

36ml, 146ml, 190ml, 352ml

Explanation:

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100x + 197.3y = 5.4

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