Answer:
Some of the internal strain energy is relieved.
There is some reduction in the number of dislocations.
The electrical conductivity is recovered to its precold-worked state.
The thermal conductivity is recovered to its precold-worked state
Explanation:
The process of the recovery of a cold-worked material happens at a very low temperature, this process involves the movement and annihilation of points where there are defects, also there is the annihilation and change in position of dislocation points which leads to forming of the subgrains and the subgrains boundaries such as tilt, twist low angle boundaries.
mechanism, in mechanical construction, the means employed to transmit and modify motion in a machine or any assemblage of mechanical parts.
The main objective of phasing out an INDUCTION MOTOR is to identify the ends of the stator coils.
<h3>What is an induction motor?</h3>
An induction motor is a device based on alternate electricity (AC) which is composed of three different stator coils.
An induction motor is a device also known as an asynchronous motor due to its irregular velocity.
In conclusion, the objective of phasing out an INDUCTION MOTOR is to identify the ends of the stator coils.
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Answer:
True
Explanation:
By definition of steady flow we have

where f(x,y,z,t) is any property of the system under consideration
=> f(x,y,z,t) = constant
The work done by a 10 HP motor when it raises a 1000 Newton weight at a vertical distance of 5 meters is <u>5kJ</u>.
Define work. Explain the rate of doing work.
Work is <u>the energy that is moved to or from an item by applying force along a displacement</u> in physics. For a constant force acting in the same direction as the motion, work is <u>easiest expressed as the product of </u><u>force </u><u>magnitude and distance traveled</u>.
Since the <u>force </u><u>transfers one unit of energy for every unit of </u><u>work </u><u>it performs</u>, the rate at which work is done and energy is used are equal.
Solution Explained:
Given,
Weight = 1000N and distance = 5m
A/Q, the work here is done in lifting then
Work = (weight) × (distance moved)
= 1000 X 5
= 5000Nm or 5000J = 5kJ
Therefore, the work done in lifting a 1000 Newton weight at a vertical distance of 5 meters is 5kJ.
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