Answer with Explanation:
We are given that
Egood=12 V
Rbatt,good=0.02ohm
Edead=10.8 V
Rbatt,dead=0.3 ohm
We have to find the current through the batteries connected in series and parallel.
When batteries are connected in series
V=Egood+Edead=12+10.8=22.8 V
R=Rbatt,good+Rbatt,dead=0.02+0.3=0.32 ohm
Current,I=
Using the formula
When the batteries are connected in parallel
V=Egood-Edead=12-10.8=1.2 V
R=0.02+0.3=0.32 ohm
Answer and Explanation: One ATP release approximately 30.5kJ/mol of energy. Using Avogadro's constant, it is known one mol corresponds to molecules, so 106 ATP molecules releases:
E =
E = J
A cell is approximately a sphere. Volume of a sphere is given by
V =
Changing radius from mm to m:
r = m
Then, volume is
V =
V = m³
Power density is given by
power = 12.8. W/m³
Power density for a the cell is 12.8. W/m³.
Power density for battery is
100 cm³ = m³
power =
power = W/m³
Comparing cell and battery, battery has a greater power density.
Answer:
The average power provided by the tension in the cable pulling the lift is = 714 W
Explanation:
Given data
Mass = 71 kg
Change in height = 123 m
When the lift moves in upward direction then in that case kinetic energy is constant & only potential energy changes.
Change in potential energy Δ PE = m g ( )
Δ PE = 71 × 9.81 × 123
Δ PE = 85670.73 J
Time = 2 min = 120 sec
So average power is given by
Therefore the average power provided by the tension in the cable pulling the lift is = 714 W