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Anestetic [448]
4 years ago
13

Static cling is an example of

Physics
1 answer:
cestrela7 [59]4 years ago
3 0
I would say c hope it helps:)
You might be interested in
1. If two objects collide and one is initially at rest, is it possible for both to be at rest after the collision? Is it possibl
NeX [460]

Answer:

(a)If two objects collide and one is initially at rest, is it possible for both to be at rest after the collision?

No. Because if you have initial momentum P⃗ ≠0 , if both of the objects were at rest after the collision the total momentum of the system would be P⃗ =0 , which violates conservation of momentum

(b)Is it possible for only one to be at rest after the collision?

Yes, that is perfectly possible. It characteristically, happens when both objects are of the same mass. When two objects of the same mass collide and Kinetic energy is conserved (Perfectly Elastic collision) then the two objects interchange velocities.

8 0
2 years ago
I put +40 points!!!
Aleonysh [2.5K]

Answer:We can solve this using the Law of Conservation of Momentum. If both marbles are in our system, the initial momentum should equal the final momentum.

The initial momentum can be solved for as so:

*  +  =

(0.06)(0.7) + (0.03)(0) = 0.042 [kg * m/s]

So if the system has an initial momentum of 0.042, it should have the same final momentum.

(0.06)(-0.2) + (0.03)() = 0.042

(0.03)() = 0.54

() = 18 [m/s]

Explanation:

5 0
3 years ago
Read 2 more answers
What is the most problem of any defective tools?​
Alexeev081 [22]

Answer:

knife or weapon

Explanation:

that could be dangerous...

8 0
3 years ago
Which correctly identifies the mass and approximate weight of the same object on Earth?
Vladimir79 [104]

Answer:

B.

Explanation:

w=mg

g=10m/s

hope this helps

4 0
3 years ago
If a 230 gram object falls from 2 meters, what is its impulse and velocity upon impact?
anastassius [24]

1.44Ns

6.3m/s

Explanation:

Given parameters:

Mass of object = 230g = 0.23g

height of fall = 2m

Unknown:

Impulse = ?

velocity on impact = ?

Solution:

We are going to apply one of the equations of motions to solve this problem.

The most appropriate one is:

       V² = U² + 2gH

where V is the final velocity

U is the initial velocity

g is acceleration due to gravity as the body falls with aid of gravity = 9.8m/s²

  H is the height of fall

since the body was initially at rest, U = O

     V² = 2gH

      V = √2 x 9.8 x 2 = 6.3m/s

 Impulse = mass x velocity  = 0.23 x 6.3 = 1.44Ns

learn more:

momentum brainly.com/question/2990238

velocity brainly.com/question/10932946

#learnwithBrainly

5 0
4 years ago
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