6. Draw a velocity-time graph for an object originally traveling at -3 m/s. The object
1 answer:
See the graph in attachment
Explanation:
In this problem we have to draw a velocity-time graph for an object travelling initially at -3 m/s, then slowing down and turning around.
In the graph, we see that the initial velocity at time t = 0 is
and it is negative, so below the x-axis.
Later, the object slows down: this means that the magnitude of its velocity increases, therefore (since the velocity is negative) the curve must go upward, approaching and reaching the x-axis (which corresponds to zero velocity).
After that, the object's velocity keep increasing, but now it is positive: this means that the object is travelling in a direction opposite to the initial direction, so it has turned around.
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(a) 2.75 rev/min
The moment of inertia of the rod rotating about its center is:
where
is its mass
L = 0.450 m is its length
Substituting,
The moment of inertia of the two rings at the beginning is
where
m = 0.200 kg is the mass of each ring
is their distance from the center of the rod
Substituting,
So the total moment of inertia at the beginning is
The initial angular velocity of the system is
The angular momentum must be conserved, so we can write:
(1)
where is the moment of inertia when the rings reach the end of the rod; in this case, the distance of the ring from the center is
so the moment of inertia of the rings is
and the total moment of inertia is
Substituting into (1), we find the final angular speed:
(b) 103.0 rev/min
When the rings leave the rod, the total moment of inertia is just equal to the moment of inertia of the rod, so:
So using again equation of conservation of the angular momentum:
We find the new final angular speed: