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Ivahew [28]
3 years ago
15

How many moles of solute particles are present in 1 ml of aqueous 0.020 m (nh4)2co3?

Chemistry
1 answer:
Dima020 [189]3 years ago
6 0
Vs = 1.0 mL = 0.001 L
c((NH4)2CO3) = <span>0.02 M
n(</span>(NH4)2CO3) = ?

For the purpose, here we will use the next equation:

c=n/V ⇒ n=cxV

n((NH4)2CO3) = 0.02M x 0.001L 

n((NH4)2CO3) = 2x10⁻⁵ mole of (NH4)2CO3 is presented in the solution


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What is the total mass of oxygen contained in 8.20g of benzoic acid (C6H5COOH)
VashaNatasha [74]

Answer:

Mass of oxygen = 2.2 g

Explanation:

Given data:

Mass of benzoic acid= 8.20 g

Mass of oxygen= ?

Solution:

Molar mass of oxygen = 16×2 g/mol

Molar mass of C₆H₅COOH = 7×12 + 1×6 + 2×16

Molar mass of C₆H₅COOH = 84 + 6 + 32

Molar mass of C₆H₅COOH = 122g/mol

Mass of oxygen in 8.20 g of C₆H₅COOH :

Mass of oxygen = 32 g.mol⁻¹/122 g.mol⁻¹ × 8.20 g

Mass of oxygen = 2.2g

4 0
3 years ago
Based on the information provided in the graph, we can see that as the independent variable increases,
Gnom [1K]
Well I have no clue on what your class is doing but to me, it looks like B. the dependent variable also increases

4 0
3 years ago
Read 2 more answers
The cell potential of the following electrochemical cell depends on the pH of the solution in the anode half-cell:Pt(s)|H2(g, 1a
meriva

Answer:

0.51

Explanation:

Given the Nernst equation;

E= E° - 0.0592/n logQ

E= 355 mV or 0.355 V

E° = 0.34 - 0= 0.34 V

n= 2(two electrons were transferred in the process)

Equation of the reaction;

H2(g) + Cu^2+(aq) -----> 2H^+(aq) + Cu(s)

Substituting values;

0.355 = 0.34 - 0.0592/2 log([H^+]/1)

0.355 - 0.34 = - 0.0296 log [H^+]

0.015/-0.0296 = log [H^+]

Antilog (-0.5068) = [H^+]

[H^+] = 0.311 M

pH = -log[H^+]

pH= - log(0.311 M)

pH = 0.51

6 0
3 years ago
Formulate the sequence of steps needed to prepare 250.0 mL of a 0.005 M aqueous solution from solid KMnO4 and pure water.
S_A_V [24]

Answer:

Molarity is a unit that measures how much moles of solute dissolved in a liter of solvent. Molarity expressed using capital M while molarity, a different unit, expressed using lower case m.  

We want to make 0.005 M solution which means we need 0.005 moles of KmnO4 per liter of water. First, we have to calculate how many grams of KMnO4 we need for the solution.

We want to make 250ml solution, so the number of moles of KMnO4 we need will be:  0.005 mol/liter *(250 ml * 1liter/1000ml)= 0.005 mol/liter  * 1/4 liter = 0.00125 moles

The molecular mass of KMnO4 is 158g/mol, so the mass of KMnO4 we need will be:  0.00125 moles *  158g/mol=  0.1975 grams

We know that we need 0.1975 g of KMnO4, now we weigh them and put it inside a dish. After that, we prepare Erlenmeyer or a volumetric flask filled with water half of the volume needed(125ml). Pour the weighted solute into the flask, stir until all solute dissolved.

Then we add water to the container slowly until its volume reaches the 250ml mark.

3 0
3 years ago
Can somebody please help me I'm begging you I'm on my last question​
nataly862011 [7]

Answer: Density (ρ) = 0.225 kilogram/cubic meter

Explanation:

4 0
3 years ago
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