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3 years ago

What is the Coriolis Force?

Physics

1 answer:

lys-0071 [83]3 years ago

7 0

It's a virtual force ... one that seems to be there but isn't really there.

When something tries to fly or flow straight, through a rotating neighborhood, it ends up flying or flowing in a curved path, AS IF there were a force acting on it to make it curve. THAT apparent force is the Coriolis force.

It's what makes air, flowing away from high pressure or into low pressure, form the big rotating pressure systems on the rotating Earth.

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True or false

ElenaW [278]

If im not mistaken it is true

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3 years ago

What force is needed to give a 4.5-kg bowling ball an acceleration of 9 m/s2?

Mrac [35]

The correct answer is 40.5 Newtons just finished the quiz and 36.5 was incorrect.

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4 years ago

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An 18-kg bicycle carrying a 62-kg girl is traveling at a speed of 7 m/s. What is the kinetic energy of the girl

Dafna11 [192]

Answer:

1960 J

Explanation:

EK = (18 kg + 62 kg) $(7.0 m/s)^{2}$ /2 = 1960 J

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3 years ago

A 0.300 kg block is pressed against a spring with a spring constant of 8050 N/m until the spring is compressed by 6.00 cm. When

natita [175]

Answer:

a) $\mu_{k} = 0.704$ , b) $R = 0.312\,m$

Explanation:

a) The minimum coeffcient of friction is computed by the following expression derived from the Principle of Energy Conservation:

$\frac{1}{2}\cdot k \cdot x^{2} = \mu_{k}\cdot m\cdot g \cdot \Delta s$

$\mu_{k} = \frac{k\cdot x^{2}}{2\cdot m\cdot g \cdot \Delta s}$

$\mu_{k} = \frac{\left(8050\,\frac{N}{m} \right)\cdot (0.06\,m)^{2}}{2\cdot (0.3\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (7\,m)}$

$\mu_{k} = 0.704$

b) The speed of the block is determined by using the Principle of Energy Conservation:

$\frac{1}{2}\cdot k \cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}$

$v = x\cdot \sqrt{\frac{k}{m} }$

$v = (0.06\,m)\cdot \sqrt{\frac{8050\,\frac{N}{m} }{0.3\,kg} }$

$v \approx 9.829\,\frac{m}{s}$

The radius of the circular loop is:

$\Sigma F_{r} = -90\,N -(0.3\,kg)\cdot (9.807\,\frac{m}{s^{2}} ) = -(0.3\,kg)\cdot \frac{v^{2}}{R}$

$\frac{\left(9.829\,\frac{m}{s}\right)^{2}}{R} = 309.807\,\frac{m}{s^{2}}$

$R = 0.312\,m$

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4 years ago

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anzhelika [568]

Answer:

Gradually Change

Explanation:

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3 years ago

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