Question

A ball hung from a vertical spring oscillates in simple harmonic motion with an angular frequency of 2.6 rad/s and an amplitude of 0.075 m. what is the maximum acceleration of the ball?

Answer 1

X position
v velocity
a acceleration
A amplitude
t time
ω angular frequency
θ phase angle

x = A cos (ωt + θ)
v = -ωA sin(ωt + θ)
a = -ω²x

a is maximum when |x| is maximum
x is maximum when v = 0

v = 0: t = 0, θ = 0
x = A
a = |-ω²A|