If the net force on a hot-air balloon is directed straight upward, which way does the acceleration point?

2. What do you get when you add the following

irga5000 [103]

a. one carbon and one oxygen?

Answer:

(1) Carbon + (1) Oxygen = Carbon monoxide (CO)

Explanation:

Carbon monoxide (CO), an odorless, colorless gas, which can cause sudden illness and death, is produced any time a fossil fuel is burned.

https://www.cdc.gov/co/default.htm

b. one carbon and two oxygen?

Answer:

(1) Carbon + (2) Oxygen = Carbon dioxide (CO2)

Explanation:

a colorless, odorless gas produced by burning carbon and organic compounds and by respiration. It is naturally present in air (about 0.03 percent) and is absorbed by plants in photosynthesis.

https://www.britannica.com/science/carbon-dioxide

c. one carbon and four chlorine?

Answer:

(1) Carbon + (4) Chlorine = Carbon tetrachloride (CCl4)

Explanation:

Carbon Tetrachloride is a clear, colorless, volatile and very stable chlorinated hydrocarbon. Carbon Tetrachloride is used as a solvent for oils and fats, as a refrigerant and as a dry-cleaning agent. Inhalation of its vapors can depress central nervous system activity and cause degeneration of the liver and kidneys. Carbon Tetrachloride is reasonably anticipated to be a human carcinogen based on evidence of carcinogenicity in experimental animals.

https://pubchem.ncbi.nlm.nih.gov/compound/carbon_tetrachloride

I hope this helps, if it dose please give brainest, and have a nice day!

8 0

2 years ago

Two groups complete an experiment requiring the mass measurement to be repeated three times in the experiment. Group I selects a

Irina18 [472]

Group 1 was more careful in choosing the person, whereas Group 2 might have been more careless.

3 0

2 years ago

Structure for reductive ozonolysis of 3,5-dimethyl-4-octene

brilliants [131]

Answer:

Scheme is Attached.

When 3,5 dimethyl-4- octene is react with ozone two products are obtain.

2-Methyl butanal and 2 pentanon.

The complete reaction is given in attached file.

3 0

2 years ago

An unknown salt is either NaF, NaCl, or NaOCl. When 0.050 mol of the salt is dissolved in water to form 0.500 L of solution, the

victus00 [196]

Answer: The unknown salt is NaF

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of salt = 0.050 moles

Volume of solution = 0.500 L

Putting values in above equation, we get:

$\text{Molarity of salt}=\frac{0.050mol}{0.500L}\\\\\text{Molarity of salt}=0.1M$

To calculate the hydroxide ion concentration, we first calculate pOH of the solution, which is:

pH + pOH = 14

We are given:

pH = 8.08

$pOH=14-8.08=5.92$

To calculate pOH of the solution, we use the equation:

$pOH=-\log[OH^-]$

Putting values in above equation, we get:

$5.92=-\log[OH^-]$

$[OH^-]=10^{-5.92}=1.202\times 10^{-6}M$

The unknown salt given are formed by the combination of weak acid and strong acid which is NaOH

The chemical equation for the hydrolysis of $X^-$ ions follows:

$X^-(aq.)+H_2O(l)\rightleftharpoons HX(aq.)+OH^-(aq.);K_b$

Initial: 0.1

At eqllm: 0.1-x x x

Concentration of $OH^-=x=1.202\times 10^{-6}M$

The expression of $K_b$ for above equation follows:

$K_b=\frac{[OH^-][HX]}{[X^-]}$

Putting values in above expression, we get:

$K_b=\frac{(1.202\times 10^{-6})\times (1.202\times 10^{-6})}{(1-(1.202\times 10^{-6}))}\\\\K_b=1.445\times 10^{-11}M$

To calculate the acid dissociation constant for the given base dissociation constant, we use the equation:

$K_w=K_b\times K_a$

where,

$K_w$ = Ionic product of water = $10^{-14}$

$K_a$ = Acid dissociation constant

$K_b$ = Base dissociation constant = $1.445\times 10^{-11}$

Putting values in above equation, we get:

$10^{-14}=1.445\times 10^{-11}\times K_a\\\\K_a=\frac{10^{-14}}{1.445\times 10^{-11}}=6.92\times 10^{-4}$

We know that:

$K_a\text{ for HF}=6.8\times 10^{-6}$

$K_a\text{ for HCl}=1.3\times 10^{6}$

$K_a\text{ for HClO}=3.0\times 10^{-8}$

So, the calculated $K_a$ is approximately equal to the $K_a$ of HF

Hence, the unknown salt is NaF

6 0

2 years ago

When a planet has the illusion of moving backwards or bouncing up and down it is exhibiting what?

Goryan [66]

Answer: It is exhibiting retrogade motion.

7 0

2 years ago