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vladimir1956 [14]
3 years ago
12

Max (15 kg) and maya (12 kg) are riding on a merry-go-round that rotates at a constant speed. max is sitting on the edge of the

merry-go-round, 2.4 m from the center, and maya is 1.2 m from the center. considering max and maya to be one system of masses, what is their moment of inertia measured with respect to the center of the merry-go-round?
Physics
2 answers:
insens350 [35]3 years ago
8 0

Answer:

103.68 NM

Explanation:

<u>Step 1:</u> identify the given parameters

Max mass = 15kg

maya mass = 12kg

max distance from the center (a)= 2.4m

maya distance from the center (b) = 1.2m

Moment of inertia = M*r²

<u>Step 2:</u> calculate the moment of inertia (I) of max

I = M*r²

I = 15*(2.4)² = 86.4NM

<u>Step 3:</u> calculate moment of inertia of Maya

I = M*r²

I = 12*(1.2)² = 17.28NM

<u>Step 4: </u>find the total moment of inertia

Total moment of inertia = max moment of inertia + Maya moment of inertia

Total moment of inertia = 86.4 NM + 17.28NM

Total moment of inertia = 103.68 NM

Lana71 [14]3 years ago
5 0
1.2 GLAD TO HELP MY FRIEND
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A 740-kg boulder is raised from a quarry 119 m deep by a long uniform chain having a mass of 550 kg . This chain is of uniform s
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