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N76 [4]
3 years ago
5

Suppose that after walking across a carpeted floor you reach for a doorknob and just before you touch it a spark jumps 0.95cm fr

om your finger to the knob. Find the minimum voltage needed between your finger and the doorknob to generate this spark. The minimum field that can produce a spark in air is 3.0x10^6 V/m. V = _______ V
Physics
1 answer:
alexandr402 [8]3 years ago
8 0

To solve this problem we will consider the definition of Minimum Energy, as the change between the minimum voltage and its distance. Mathematically it can be written as

E_{min} = \frac{V_{min}}{r}

Rearranging to find the Voltage,

V_{min} = E_{min} \times r

Replacing,

V_{min} = (3.0) \times (0.95*10^4)

V_{min} = 28500V

Therefore the minimum voltage needed between your finger and the doorknob to generate this spark is 28.5kV

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A radar used to detect the presence of aircraft receives a pulse that has reflected off an object 5 ✕ 10−5 s after it was transm
Sunny_sXe [5.5K]

Answer:

7500 m

Explanation:

The radar emits an electromagnetic wave that travels towards the object and then it is reflected back to the radar.

We can call L the distance between the radar and the object; this means that the electromagnetic wave travels twice this distance, so

d = 2L

In a time of

t=5\cdot 10^{-5}s

Electromagnetic waves travel in a vacuum at the speed of light, which is equal to

c=3.0\cdot 10^8 m/s

Since the electromagnetic wave travels with constant speed, we can use the equation for uniform motion ,so:

d=vt (1)

where

v=c=3.0\cdot 10^8 m/s

t=5\cdot 10^{-5}s

d=2L, where L is the distance between the radar and the object

Re-arranging eq(1) and substituting, we find L:

L=\frac{vt}{2}=\frac{(3.0\cdot 10^8)(5\cdot 10^{-5})}{2}=7500 m

7 0
4 years ago
A toy cart moves with a kinetic energy of 30 J. If its speed is doubled, what is its kinetic energy?
klio [65]

Explanation:

KE is directly proportional to the square of velocity / speed.

if speed is 2 times (doubled) the KE will be

{2}^{2}

= 4 times the original KE

4 \times (30)

= 120 \: j

8 0
3 years ago
A 5000kg car traveling at 40m/s crashes into a wall and comes to a complete stop in 10s. What was the force on the wall? solve s
IrinaK [193]

Answer:

20,000 N

Explanation:

First find the acceleration:

a = Δv / Δt

a = (0 − 40 m/s) / 10 s

a = -4 m/s²

Next use Newton's second law to find the force on the car:

F = ma

F = (5000 kg) (-4 m/s²)

F = -20,000 N

According to Newton's third law, the force on the wall is equal and opposite the force on the car.

F = 20,000 N

4 0
3 years ago
Consider a motor that exerts a constant torque of 25.0 nâ‹…m to a horizontal platform whose moment of inertia is 50.0 kgâ‹…m2. A
Crazy boy [7]

Answer:

W = 1884J

Explanation:

This question is incomplete. The original question was:

<em>Consider a motor that exerts a constant torque of 25.0 N.m to a horizontal platform whose moment of inertia is 50.0kg.m^2 . Assume that the platform is initially at rest and the torque is applied for 12.0rotations . Neglect friction. </em>

<em> How much work W does the motor do on the platform during this process?  Enter your answer in joules to four significant figures.</em>

The amount of work done by the motor is given by:

W=\Delta K

W= 1/2*I*\omega f^2-1/2*I*\omega o^2

Where I = 50kg.m^2 and ωo = rad/s. We need to calculate ωf.

By using kinematics:

\omega f^2=\omega o^2+2*\alpha*\theta

But we don't have the acceleration yet. So, we have to calculate it by making a sum of torque:

\tau=I*\alpha

\alpha=\tau/I     =>     \alpha = 0.5rad/s^2

Now we can calculate the final velocity:

\omega f = 8.68rad/s

Finally, we calculate the total work:

W= 1/2*I*\omega f^2 = 1883.56J

Since the question asked to "<em>Enter your answer in joules to four significant figures.</em>":

W = 1884J

3 0
3 years ago
Describe the responses of the human ear to sound waves coming from the
maria [59]

If the sound comes from the right side, the waves reach the right ear before the left ear. if the sound comes from the left side, the waves reach the left ear before the right ear. The difference between the phases of waves reaching both ears is detected by the ears and then interpreted by the brain

8 0
3 years ago
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