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kirill115 [55]
3 years ago
14

Explain how you would find the units for acceleration in a problem?

Physics
1 answer:
deff fn [24]3 years ago
6 0

Answer:

Calculating acceleration involves dividing velocity by time — or in terms of SI units, dividing the meter per second [m/s] by the second [s]. Dividing distance by time twice is the same as dividing distance by the square of time. Thus the SI unit of acceleration is the meter per second squared .

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Two identical metal spheres a and b are connected by a plastic rod. both are initially neutral. 1.0×1012 electrons are added to
Ann [662]
The plastic rod is made of insulator (plastic), so it does not allow charges moving from one sphere to another. This means that all the electrons given to sphere A will remain on sphere A.

The number of electrons initially given to sphere A is N=1.0 \cdot 10^{12}, and since the charge of 1 electron is e=-1.6 \cdot 10^{-19} C, the net charge left on sphere A after the removal of the rod will be
Q=N e = 1.0 \cdot 10^{12}(-1.6 \cdot 10^{-19} C)=-1.6.0 \cdot 10^{-7} C
8 0
3 years ago
Read 2 more answers
Paula ran a total of 72meters directly toward school at a constant velocity. She ran one-third of that distance in 8seconds. Wha
Nezavi [6.7K]

Answer:

3 meters per second

Explanation:

72 divided by 3= 24 meters in 8 seconds

24/8= 3, so 3 meters per second

3 0
3 years ago
La estrella mas proxima a la tierra esta a 2 años de luz. Calcula esta distancia en unidades del SI
tino4ka555 [31]

Answer:

2\ ly=1.89\times 10^{16}\ m

Explanation:

The question says that, "The closest star to the earth is 2 light years away. Calculate this distance in SI units".

Given that,

The distance between the closest star and the Earth is 2 light years.

The SI unit of distance is m. It means we need to convert light years to meters. We know that,

1\ ly=9.461\times 10^{15}\ m

2 light-years means,

2\ ly=2\times 9.461\times 10^{15}\ m\\\\=1.89\times 10^{16}\ m

So, the required distance is equal to 1.89\times 10^{16}\ m.

5 0
3 years ago
When red light and green light shine on the same place on a piece of white paper, the spot appears t obe?
katen-ka-za [31]
When red light and green lights shine on the same place on a piece of white paper, the spot appears to be Yellow in color. Complementary colors are always located directly across from each other on the graphic. For example cyan is located across from red, magenta across from green, and yellow across from blue. When primary color mix the produce secondary colors , for example a red light and a green light will combine to form a yellow color. The production of various colors of light by the mixing of the three primary colors of light is known as color addition.
5 0
4 years ago
Read 2 more answers
An unknown source plays a pitch of middle C (262 Hz). How fast would the sound wave from this source have to travel to raise
Viefleur [7K]

Answer:

The sound travels at v_{s}=11.4 \mathrm{m} / \mathrm{s}

Option: c

Explanation:

Unknown source plays of middle C (fs) = 262 Hz

The sound wave from this source have to travel to raise the pitch to C sharp is (fd) = 272 Hz

\begin{array}{l}{velocity of sound in air(v)=343 \mathrm{m} / \mathrm{s}, f_{\mathrm{s}}=262 \mathrm{Hz}, f_{\mathrm{d}}=271 \mathrm{Hz}} \\ {velocity of receiver(v_{\mathrm{d}})=0 \mathrm{m} / \mathrm{s},velocity of source( v_{\mathrm{s}}) \text { is unknown }}\end{array}

\text { Speed of sound } \mathrm{V}_{\mathrm{S}}=343 \mathrm{m} / \mathrm{s}

f_{\mathrm{d}}=f_{\mathrm{s}}\left(\frac{v-v_{\mathrm{d}}}{v-v_{\mathrm{s}}}\right)

\frac{f_{d}}{f_{s}}=\left(\frac{v-v_{d}}{v-v_{s}}\right)

\left(v-v_{s}\right)=\frac{f_{s}}{f_{d}}\left(v-v_{d}\right)

v_{s}=v-\frac{f_{s}}{f_{d}}\left(v-v_{d}\right)

Substitute the given values in the formula,

v_{s}=343+\frac{262}{271}(343-0)

v_{s}=343+0.966(343)

v_{s}=343-331.33

v_{s}=11.4 \mathrm{m} / \mathrm{s}

Therefore, The sound travels at v_{s}=11.4 \mathrm{m} / \mathrm{s}

4 0
3 years ago
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