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3 years ago

Hi, how do you draw two opposite rays and name them? Is it two of these "<--->" that intersect? Or two separate rays?

1 answer:

3 0

Opposite rays

From the term “opposite” which is derived from the Latin word “oppositus” meaning “set against”, Opposite Rays are two rays which start from one common point and is pointed outwards in an exact opposite direction from each other forming a straight line.

<span>For example, this is Line A <<<+========== ;
this is Line B ==========+>>></span>

Line A and Line B are two rays but they can only be called Opposite Rays when they both start from a common point which is Letter O; thus, forming a straight line.

A <<<+========== O ==========+>>> B

When there are opposite rays, points A, O, and B are collinear, meaning these points are present in the same straight line.

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Two electrons, each with mass mmm and charge qqq, are released from positions very far from each other. With respect to a certai

lana66690 [7]

The answer & explanation for this question is given in the attachment below.

3 0

3 years ago

The following table lists the work functions of a few commonmetals, measured in electron volts.

steposvetlana [31]

Answer:

Lithium

Explanation:

The equation for the photoelectric effect is

$\frac{hc}{\lambda}= \phi + K_{max}$

where

$\frac{hc}{\lambda}$ is the energy of the incident photon, with

h being the Planck constant

c is the speed of light

$\lambda$ is the wavelength of the photon

$\phi$ is the work function of the metal (the minimum energy needed to extract the photoelectron from the metal)

$K_{max}$ is the maximum kinetic energy of the emitted photoelectrons

In this problem, we have

$\lambda= 190 nm = 1.9\cdot 10^{-7}m$ is the wavelength of the incident photon

$K_{max}=4.0 eV$ is the maximum kinetic energy of the electrons

First of all we can find the energy of the incident photon

$E=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1.90\cdot 10^{-7} m}=1.05\cdot 10^{-18} J$

Converting into electronvolts,

$E=\frac{1.05\cdot 10^{-18} J}{1.6\cdot 10^{-19} J/eV}=6.6 eV$

So now we can re-arrange the equation of the photoelectric effect to find the work function of the metal

$\phi = E-K_{max}=6.6 eV - 4.0 eV=2.6 eV$

So the metal is most likely Lithium, which has a work function of 2.5 eV.

3 0

3 years ago

Helppppppl!!!!!!!!!!!

RUDIKE [14]

Answer:

I think deposition of C is the oldest deposit

8 0

3 years ago

The whooping crane (Grus americana) is the tallest bird native to North America. It almost went extinct in the 1900s; in 1938, t

grin007 [14]

Answer:

The value is $a = 2.7183$

Explanation:

From the question we are told that

The relationship between the number of whooping cranes and the number of decades is $ln N = 2.85 + 0.039t$

The exponential relationship is $N = na^{kt}$

Now from the given equation we have that

$N = e^{2.85 + 0.039t}$

$N = 17.29 e^{0.039t}$

So comparing this equation obtained an the given exponential relationship we have that

$n = 17.29$

$k = 0.039$

$a = e = 2.7183$

$a = 2.7183$

7 0

3 years ago

Charge is uniformly distributed around a ring of radius R and the resulting electric field magnitude E is measured along the rin

Arte-miy333 [17]

Answer:

$x=\dfrac{r}{\sqrt2}$

Explanation:

Given that

Radius =r

Electric filed =E

Q=Charge on the ring

The electric filed at distance x given as

$E=K\dfrac{Q}{(r^2+x^2)^{3/2}}$

For maximum condition

$\dfrac{dE}{dx}=0$

$E=K{Q}{(r^2+x^2)^{-3/2}}$

$\dfrac{dE}{dx}=K{Q}{(r^2+x^2)^{-3/2}}-\dfrac{3}{2}\times 2\times x\times K{Q}{(r^2+x^2)^{-5/2}}$

For maximum condition

$\dfrac{dE}{dx}=0$

$K{Q}{(r^2+x^2)^{-3/2}}-\dfrac{3}{2}\times 2\times x\times K{Q}{(r^2+x^2)^{-5/2}}=0$

$r^2+x^2-3x^2=0$

$x=\dfrac{r}{\sqrt2}$

At $x=\dfrac{r}{\sqrt2}$ the electric field will be maximum.

3 0

3 years ago