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jeka94
3 years ago
12

Hi, how do you draw two opposite rays and name them? Is it two of these "<--->" that intersect? Or two separate rays?

Physics
1 answer:
Artyom0805 [142]3 years ago
3 0
Opposite rays

From the term “opposite” which is derived from the Latin word “oppositus” meaning “set against”, Opposite Rays are two rays which start from one common point and is pointed outwards in an exact opposite direction from each other forming a straight line.

<span>For example,  this is Line A  <<<+========== ;
                       this is Line B ==========+>>></span>

Line A and Line B are two rays but they can only be called Opposite Rays when they both start from a common point which is Letter O; thus, forming a straight line.

                   A <<<+========== O ==========+>>> B

When there are opposite rays, points A, O, and B are collinear, meaning these points are present in the same straight line.



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We can detect 21-cm emission from other galaxies as well as from our own Galaxy. However, 21-cm emission from our own Galaxy fil
amid [387]

Answer:

Explanation:

Galaxies are in constant motion with respect to each other . For example Andromeda galaxy is approaching our galaxy ( milky way ) at about 110 km /s . So we will observe blue shift in the spectrum of radiation coming from  this galaxy . In this way, we can distinguish between radiation coming from our galaxy and that coming from other galaxy . Spectrum of radiation coming from other galaxy must  have either red or blue  shift .

6 0
3 years ago
What must occur for work to be done on an object?
stiv31 [10]
The answer is D since work done must have displacement..if theres force but no displacement there will be no work done based on W=Fs
4 0
3 years ago
Read 2 more answers
A 2,537-kg truck moving at 14 m/s strikes a car waiting at a traffic light, hooking bumpers. The two continue to move together a
slavikrds [6]

Answer:

1902.75 kg

Explanation:

From Law of conservation of momentum,

m₁u₁ + m₂u₂ = V (m₁ + m₂).................... Equation 1

make m₂ the subject of the equation,

m₂ = (m₁V - m₁u₁)/(u₂-V)..................... Equation 2

Where m₁ = mass of the truck, m₂ = mass of the car, u₁ initial velocity of the truck, u₂ = initial velocity of the car V = common velocity

Given: m₁ = 2537 kg, u₁ = 14, V= 8 m/s, u₂ = 0 m/s ( as the car was at rest waiting at a traffic light)

Substituting into equation 2.

m₂ =[2537(8) - 2537(14)]/(0-8)

m₂ = (20296-35518)/-8

m₂ = -15222/-8

m₂ = 1902.75 kg.

Thus the mass of the car = 1902.75 kg

5 0
3 years ago
hat are the wavelengths of peak intensity and the corresponding spectral regions for radiating objects at (a) normal human body
bagirrra123 [75]

Answer:

(a)

\lambda _{m}=9.332 \times 10^{-6}m

(b)

\lambda _{m}=1.632 \times 10^{-6}m

(c) \lambda _{m}=4.988 \times 10^{-7}m

 

Explanation:

According to the Wein's displacement law

\lambda _{m}\times T = b

Where, T be the absolute temperature and b is the Wein's displacement constant.

b = 2.898 x 10^-3 m-K

(a) T = 37°C = 37 + 273 = 310 K

\lambda _{m}=\frac{b}{T}

\lambda _{m}=\frac{2.893\times 10^{-3}}{310}

\lambda _{m}=9.332 \times 10^{-6}m

(b) T = 1500°C = 1500 + 273 = 1773 K

\lambda _{m}=\frac{b}{T}

\lambda _{m}=\frac{2.893\times 10^{-3}}{1773}

\lambda _{m}=1.632 \times 10^{-6}m

(c) T = 5800 K

\lambda _{m}=\frac{b}{T}

\lambda _{m}=\frac{2.893\times 10^{-3}}{5800}

\lambda _{m}=4.988 \times 10^{-7}m

5 0
3 years ago
A runner completes the 300 meter dash in 38 seconds what is the speed of the runner? Round your answer to the nearest tenth
grandymaker [24]
38 = 300
60 = ?
300 × 60 ÷ 38
1800 ÷ 38 = 47.368
The answer is 47.4 m per hour
7 0
3 years ago
Read 2 more answers
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