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jeka94
3 years ago
12

Hi, how do you draw two opposite rays and name them? Is it two of these "<--->" that intersect? Or two separate rays?

Physics
1 answer:
Artyom0805 [142]3 years ago
3 0
Opposite rays

From the term “opposite” which is derived from the Latin word “oppositus” meaning “set against”, Opposite Rays are two rays which start from one common point and is pointed outwards in an exact opposite direction from each other forming a straight line.

<span>For example,  this is Line A  <<<+========== ;
                       this is Line B ==========+>>></span>

Line A and Line B are two rays but they can only be called Opposite Rays when they both start from a common point which is Letter O; thus, forming a straight line.

                   A <<<+========== O ==========+>>> B

When there are opposite rays, points A, O, and B are collinear, meaning these points are present in the same straight line.



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Car A is parked on a hill and Car B is driving down a level highway. Which statement best describes the two cars? A) Car A has k
12345 [234]
The answer is b because kinetic energy is the energy of motion, while potential energy is the energy stored in an object because of its position.
5 0
4 years ago
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You’re driving your car towards an intersection. A Porsche is stopped at the red light. You’re traveling at 36 km/h (10 m/s). As
34kurt

Your position at time t, relative to the stop line:

x_1=-15\,\mathrm m+\left(10\dfrac{\rm m}{\rm s}\right)t

The Porsche's position:

x_2=\dfrac12\left(3\dfrac{\rm m}{\mathrm s^2}\right)t^2

a. You pass the Porsche immediately after the time it takes for x_1=x_2:

-15\,\mathrm m+\left(10\dfrac{\rm m}{\rm s}\right)t=\dfrac12\left(3\dfrac{\rm m}{\mathrm s^2}\right)t^2\implies t=2.3\,\rm s

at which point you both will have traveled 7.8 m from the stop line.

b. The equation in part (a) has two solutions. The Porsche passes you at the second solution of about t=4.4\,\rm s, at which point you both will have traveled 29 m.

c. At time t, the Porsche is moving at velocity

v=\left(3\dfrac{\rm m}{\mathrm s^2}\right)t

so that at the moment it passes you, its speed is 13 m/s, which is about 46.8 km/h and below the speed limit, so neither of you will be pulled over.

6 0
4 years ago
A string is attached to the rear-view mirror of a car. A ball is hanging at the other end of the string. The car is driving arou
Alekssandra [29.7K]

Answer:

<em>c. tension, gravity, and the centripetal force</em>

<em></em>

Explanation:

The ball experiences a variety of force as explained below.

Gravity force acts on the body due to its mass and the acceleration due to gravity. The gravity force on every object on earth due to its mass keeps all object on the surface of the earth.

Although the car moves around in circle, centripetal towards the center of the radius of turn exists on the ball. This centripetal force is due to the constantly changing direction of the circular motion, resulting in a force away from the center. The centripetal force keeps the ball from swinging off away from the center of turn.

Tension force on the string holds the ball against falling towards the earth under its own weight, and also from swinging away from the center of turn of the car. Tension force holds the ball relatively fixed in its vertical position in the car.

3 0
4 years ago
When light of wavelength 160 nm falls on a gold surface, electrons having a maximum kinetic energy of 2. 66 ev are emitted. Find
enyata [817]

When the light of wavelength is falling on gold surface, the electrons begin to exchange energies.

a)The work function in eV is Φ =5.097 eV.

b) The cut-off wavelength is λ₀ = 243.71 nm

c) The frequency is ν₀  =1.231 × 10¹⁵ Hz

<h3>What is work function?</h3>

The energy needed for a particle to escape and break through the surface.

The kinetic energy of the light emitted is 2.66 eV and wavelength of the light is 160 nm = 160 × 10⁻⁹ m.

a) The work function of the gold for given maximum kinetic energy is

Φ = hc / λ  - K.Emax

Substituting 6.626 × 10⁻³⁴ J.s for h, 3 × 10⁸ m/s for c and 2.66 eV for K.Emax, work function will be

Φ =8.16 × 10⁻¹⁹ J

1 eV = 1.6 × 10⁻¹⁹

The work function in eV is Φ =5.097 eV.

b) The cutoff wavelength is related to work function as

λ₀ = hc / Φ

Substitute the corresponding values into the equation, we get the cut off wavelength

λ₀ = 243.71 nm

c) The frequency corresponding to the cut-off wavelength is

ν₀ = c / λ₀

Substitute the corresponding values into the equation, we get the frequency,

ν₀  =1.231 × 10¹⁵ Hz

Therefore, the values for the following are

a)The work function in eV is Φ =5.097 eV.

b) The cut-off wavelength is λ₀ = 243.71 nm

c) The frequency is ν₀  =1.231 × 10¹⁵ Hz

Learn more about wave function.

brainly.com/question/17484291

#SPJ4

3 0
2 years ago
A fish is 17.9 cm from the front surface of a fish bowl of radius 45 cm. Where does the fish appear to be to someone in air view
AleksAgata [21]

Answer:

Fish will appear at distance 14.9 cm from the surface of bowl

Explanation:

As we know that fish is floating inside the water in fish bowl while it is observed from outside in air

so we have

\frac{\mu_2}{d_i} - \frac{\mu_1}{d_o} = \frac{\mu_2 - \mu_1}{R}

here we have

\mu_2 = 1

\mu_1 = 1.33

d_o = 17.9 cm

R = 45 cm

now we have

\frac{1}{d_i} - \frac{1.33}{17.9} = \frac{1 - 1.33}{45}

d_i = 14.9 cm

7 0
4 years ago
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