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jeka94
2 years ago
12

Hi, how do you draw two opposite rays and name them? Is it two of these "<--->" that intersect? Or two separate rays?

Physics
1 answer:
Artyom0805 [142]2 years ago
3 0
Opposite rays

From the term “opposite” which is derived from the Latin word “oppositus” meaning “set against”, Opposite Rays are two rays which start from one common point and is pointed outwards in an exact opposite direction from each other forming a straight line.

<span>For example,  this is Line A  <<<+========== ;
                       this is Line B ==========+>>></span>

Line A and Line B are two rays but they can only be called Opposite Rays when they both start from a common point which is Letter O; thus, forming a straight line.

                   A <<<+========== O ==========+>>> B

When there are opposite rays, points A, O, and B are collinear, meaning these points are present in the same straight line.



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Five properties of magnet​
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2 years ago
A 4.40-kilogram hoop starts from rest at a height 1.70 m above the base of an inclined plane and rolls down under the influence
Anestetic [448]

Answer:

The linear velocity is  v=4.08m/s

Explanation:

According to the law of conservation of energy

   The potential energy possessed by the  hoop at the top of the inclined plane is converted to the kinetic energy at the foot of the inclined plane

        The kinetic energy can be mathematically represented as

                    KE = \frac{mv^2}{2} + \frac{Iw}{2}

Where I is the moment of inertia possessed by the hoop  which is mathematically represented as

                 I = mr^2

Here R is the radius of the hoop

         w is the angular velocity which the hoop has at the bottom of the lower part of the inclined plane which is mathematically represented as

                          w = \frac{v}{r}

Where v linear speed of the hoop's center of mass just as the hoop leaves the incline and rolls onto a horizontal surface

      Now expressing the above statement mathematically

            potential \ energy = \frac{mv^2}{y} + \frac{Iw^2}{2}

               mgh = \frac{mv^2}{y} + \frac{Iw^2}{2}

=>            mgh =\frac{mv^2}{2} + \frac{(mr^2)(\frac{v}{r})^2 }{2}  

=>          mgh = \frac{mv^2}{2} + \frac{mv^2}{2}

=>           mgh = mv^2

=>              v = \sqrt{gh}

Substituting values

                v = \sqrt{9.81 * 1.7}

                  v=4.08m/s

4 0
2 years ago
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A roller coaster starts from rest at its highest point and then descends on its (frictionless) track. Its speed is 36 m/s when i
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Answer:

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