All categories

3 years ago

Which statement about projectile motion is true?

Physics

2 answers:

Shalnov [3]3 years ago

4 0

Answer:

D. The hang time of a projectile is greatest for a vertical launch.

Explanation:

As we know that range of projectile is given by the formula

$R = \frac{v^2sin(2\theta)}{g}$

so here as we increase the angle till 45 degree then the range will decrease but if we increase the angle more than 45 degree then the range will start decreasing

Also we know that time of flight is given by the formula

$T = \frac{2vsin\theta}{g}$

since it depends on the vertical component of the motion so we can say that hang time can be determine by vertical components of the motion

So maximum hang time is possible only when angle of projection is 90 degree

so correct answer will be

D. The hang time of a projectile is greatest for a vertical launch.

Svetllana [295]3 years ago

3 0

C. The range of a projectile increases with an increase in the angle of launch.

You might be interested in

If a small number of tree frogs migrate to a mat of vegetation that is already home to an established population of tree frogs a

Bingel [31]

Answer:

Explanation:

Gene flow is the transfer of genetic variation from one population to another

5 0

3 years ago

Mountains are part of which earth sphere?? Am I correct?

sammy [17]

You are correct. Mountains are part of the lithosphere.

8 0

3 years ago

Read 2 more answers

2. A portion of the body receives 0.15 mGy from radiation with a quality factor Q = 6 and 0.22 mGy from radiation with Q = 10. (

DiKsa [7]

Answer with Explanation:

We are given that

$D_1=0.15mGy$

$D_2=0.22mGy$

$Q_1=6$

$Q_2=10$

a.We have to find the total dose

Total dose= $D=D_1+D_2$

Using the formula then, we get

$D=0.15+0.22$

$D=0.37mGy$

b.We have to find the total dose equivalent

Total dose equivalent=H= $D_1Q_1+D_2Q_2$

Using the formula

$H=0.15(6)+0.22(10)$

H=3.1mSv

7 0

3 years ago

What average force is needed to accelerate a 7.00-gram pellet from rest to 155 m/s over a distance of 0.600 m along the barrel o

leonid [27]

Answer: The force needed is 140.22 Newtons.

Explanation:

The key assumption in this problem is that the acceleration is constant along the path of the barrel bringing the pellet from velocity 0 to 155 m/s. This means the velocity is linearly increasing in time.

The force exerted on the pellet is

F = m a

In order to calculate the acceleration, given the displacement d,

$d = \frac{1}{2}at^2\implies a=\frac{2d}{t^2}$

we will need to determine the time t it took for the pellet to make the distance through the barrel of 0.6m. That time can be determined using the average velocity of the pellet while traveling through the barrel. Since the velocity is a linear function of time, as mentioned above, the average is easy to calculate as:

$\overline{v}=\frac{1}{2}(v_{end}-v_{start})=\frac{1}{2}(155-0)\frac{m}{s}=77.5\frac{m}{s}$