To answer this question, we will use the equation of Clausius-Clapeyron which can be written as follows:
ln(P1/P2) = ΔH/R x (1/T2 - 1/T1)
Now, let's check the parameters in this equation:
P1 is the normal pressure of the vapor which is 4.24 kPa
T1 is the boiling point at this pressure which is 293 K
ΔH is the heat of vaporization given as 39.9 kJ/mol
T2 is given as 355.3 K
and we need to calculate P2
Substitute in the equation to get P2 as follows:
ln(4.24/P2) = 39.9/0.008314 x (1/355.3 - 1/293)
P2 = 101.2 kPa = 0.998766 atm
<u>Answer:</u> The correct answer is Option B.
<u>Explanation:</u>
There are 3 sub-atomic particles present in an atom. They are: Electrons, protons and neutrons.
- <u>Electrons:</u> They are negatively charged particles and are present around the nucleus in the orbits.
- <u>Protons:</u> They are positively charged particles and are present inside the nucleus of an atom.
- <u>Neutrons:</u> They are neutral particles which means they do not carry any charge. They are present in the nucleus of an atom.
Hence, the correct answer is Option B.
Answer:
the heat given off is 75 J.
Explanation:
Given;
latent heat of fusion of lead, L= 25 J/g
mass of liquid lead, m = 3.0g
The heat given off is calculated as;
H = Lm
Where;
H is the quantity of heat given off
H = 25 x 3
H = 75 J.
Therefore, the heat given off is 75 J.
Answer:
mL
Explanation:
Atmospheres (atn), Torr, and mm of Hg are all units of pressure but mL is a unit of volume, not pressure.
