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yKpoI14uk [10]
3 years ago
8

Why is a chemical equilibrium described as dynamic? Because maximum randomness has been achieved. Because the pressure and tempe

rature do not change. Because both reactants and products continue to form. Because the concentrations of chemical species remain constant. Because the reactant and product molecules are in constant motion.
Chemistry
2 answers:
777dan777 [17]3 years ago
5 0
Because both reactants and products continue to form. Option (c) is the answer.
nexus9112 [7]3 years ago
5 0

Answer: Because both reactants and products continue to form.

Explanation: Characteristics of chemical equilibrium:

Equilibrium is reached when the rate of the forward reaction is equal to the rate of the reverse reaction

Chemical equilibrium is attained in a closed system.

The macroscopic properties remains constant like: volume, pressure, energy etc.

The concentration of the reactants and products remain constant.

The reactants and products keep on forming.

Thus  when equilibrium is reached, the reaction is still occurring in both directions, but the rates of forward and backward direction are equal so there is no net change in the concentrations of the reactants or products.

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Answer would be C, Physical Change, it's similar to crumpling up a piece of paper

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A gas has a volume of 1.8Lat−26◦Cand 147 kPa. At what temperature would the gas occupy 1.33 L at 217 kPa?
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Answer: At temperature of 269 K the gas would occupy 1.33 L at 217 kPa

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 147 kPa

P_2 = final pressure of gas = 217 kPa

V_1 = initial volume of gas = 1.8 L

V_2 = final volume of gas = 1.33 L

T_1 = initial temperature of gas = -26^oC=273-26=247K

T_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{147kPa\times 1.8L}{247K}=\frac{217kPa\times 1.33L}{T_1}

T_2=269K

Thus at 269 K temperature the gas would occupy 1.33 L at 217 kPa

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