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stepan [7]
3 years ago
8

Carbon tetrachloride will have which shape?

Chemistry
2 answers:
taurus [48]3 years ago
8 0
Your answer should be A
erica [24]3 years ago
5 0
I believe the answer is C) tetrahedral. I hope this helps! :)
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Which is most likely why many scientists reject the cold fusion theory?
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The original results have not been replicated consistently and reliably.

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3 years ago
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How many neutrons does element X have if its atomic number is 22 and its mass number is 99?
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77.

To find the answer u have to subtract the atomic mass from the atomic number.
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4 years ago
Which sentences describe alpha particles?
kakasveta [241]

Answer:

1. Alpha particles consist of two protons and two neutrons.

Explanation:

Alpha particles are generally produced in the process of alpha decay, a radio active decay in which an atom loses an helium atom.

AN alpha particle is identical  to the helium particle. The helium particle has mass number of 4 and atomic number of 2. This means;

Number of protons = 2

Number of neutrons = Mass Number - Atomic Number = 2

The correct option is option 1.

8 0
3 years ago
Which substance is a diatoic molecule?<br> A] He<br> B] O2<br> C] CO2<br> D] H2O
PilotLPTM [1.2K]
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6 0
3 years ago
How much work is needed to assemble an atomic nucleus containing three protons (such as Be) if we model it as an equilateral tri
klio [65]

Answer:

2.16 MeV

Explanation:

To determine the amount of work done that is needed to assemble the atomic mass; we need to apply the equation;

U = \frac{3}{4 \pi E_o} (\frac{e^2}{r})

where:

\frac{1}{4 \pi E_o} = proportionality constant = (9*10^9N.m^2/C^2)

e = magnitude of the charge of each electron = (1.6*10^{-19} C)^2

r = length of each side of the vertex = (2.00*10^{-15}m)

So; replacing our values into above equation; we have:

U = 3\frac{(9*10^9N.m^2/C^2)(1.6*10^{-19} C)^2}{(2.00*10^{-15}m)}

U = 3.456 × 10 ⁻¹³ J

If we have to convert our unit from J to Mev; then we are going to have:

U = 3.456 × 10 ⁻¹³ J (\frac{1 MeV}{1.602*10^{-13}J})

U = 2.16 MeV

Therefore, the amount of work done needed to assemble an atomic nucleus =  2.16 MeV

8 0
3 years ago
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