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bonufazy [111]
3 years ago
9

If a transformer doubles its input voltage, what is the current in the secondary coil if the primary coil is 10 A.

Physics
1 answer:
Alja [10]3 years ago
5 0

Answer:

20Amp

Explanation:

Using the transformer formula

Vs/Vp = Ns/Np = Ip/Is

Vs/Vp = Ip/Is

Vp is the primary voltage = input voltage

Vs is the secondary voltage = output voltage

Ip is the current in the primary coil

Is is the amount of current in the secondary coil.

If the transformer doubles its input voltage Vp, its output voltage Vs will be

decreased by 2 but the output current will be doubled

Given the input current Ip = 10A, the current in the secondary coil (output current) will be doubled i.e Is = 2(10) = 20A

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Rina8888 [55]

Answer:

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7 0
3 years ago
Explain the advantages of using parallel circuits to series circuits in wiring rooms
irina [24]

The major advantage of parallel circuit which makes it advantageous in the application of wiring rooms are the supply of equal voltage across each circuit, which is not present in series circuit.

<u> Explanation:</u>

The use of parallel circuit is preferred over series circuit while wiring the room as the parallel gives the same voltage across every circuit which keeps it safe from damaging or burning as they give consistent voltage.

Apart from this, the parallel circuit allows you for independent operation without letting use of all the equipment present in the room. Then there is scope for additional components without changing the voltage.

5 0
3 years ago
Luis wanted to know which of his 4 toy cars is the fastest. He conducted an experime and recorded his results in the table shown
Murrr4er [49]
The dependent variable was the time and the independent variable was thecars
6 0
4 years ago
One car has two and a half times the mass of a second car, but only half as much kinetic energy. When both cars increase their s
Leokris [45]

Answer:

v_1 = 7.96 m/s

v_2 = 17.8 m/s

Explanation:

Let the mass of the other car is "m" and its kinetic energy is

K = \frac{1}{2}mv^2

now the mass of the first car is two and half times and its kinetic energy is half that of other car

so we will have

\frac{1}{2}(2.5m)v_1^2 = \frac{1}{2}(\frac{1}{2}mv^2)

2.5 v_1^2 = 0.5 v^2

v_1 = 0.447 v

now speed of both cars is increased by value of 9 m/s

so now we will have same kinetic energy for both cars

\frac{1}{2}(2.5 m)(0.447v + 9)^2 = \frac{1}{2}m(v + 9)^2

2.5(0.447 v + 9)^2 = (v + 9)^2

1.58(0.447v + 9) = v + 9

0.293v = 5.22

v = 17.8 m/s

so speed of first car is

v_1 = 0.447 v = 7.96 m/s

v_2 = 17.8 m/s

3 0
4 years ago
A force of 10N propels a 350-g toy rocket upwards. The rocket initially starts from rest and the rocket motor burns for 0.1 s. W
dimaraw [331]
Impulse=force x time
=10N x 0.1s
=1.0Ns
5 0
3 years ago
Read 2 more answers
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