Answer:
Current in a parallel circuit = 0.61 amps (Approx)
Explanation:
Given:
Voltage V = 6 volt
Two resistors = 17.2 , 22.4 in parallel circuit
Find:
Current in a parallel circuit
Computation:
1/R = 1/r1 + 1 / r2
1/R = 1/17.2 + 1 / 22.4
R = 9.73 ohms (Approx)
Current in a parallel circuit = V / R
Current in a parallel circuit = 6 / 9.73
Current in a parallel circuit = 0.61 amps (Approx)
The forces that push upward on an indoor skydiver are lift force and air resistance.
The forces that act on a skydiver moving downwards includes, gravity due to his weight, air resistance and lift force.
The downward forces on the indoor skydiver include the following;
- <em>gravity due to its weight</em>
- <em>downward force due its acceleration</em>
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The upward force on the indoor skydiver include the following;
- <em>lift force</em>
- <em>air resistance</em>
Thus, we can conclude that the forces that push upward on an indoor skydiver are lift force and air resistance.
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Answer:

Explanation:
So suppose the axis of rotation is perpendicular to the surface of the disk, then the moment of inertia can be calculated as the following:

We can convert the rotation speed in term of 0.8 seconds per revolution to the angular velocity knowing that each revolution is 2π

Then the rotational angular momentum of the disk is:

In case the axis of rotation is parallel with the surface, the moment of inertia would have a formula of:

Given
v = 343 m/s
ac = 5g
ac = 5*9.8 m/s^2
ac = 49 m/s^2
where,
v: velocity
ac = centripetal aceleration
Procedure
We call the acceleration of an object moving in uniform circular motion—resulting from a net external force—the centripetal acceleration ac; centripetal means “toward the center” or “center seeking”.
Formula

The minimum radius not to exceed the centripetal acceleration is 2401 m.
Answer:
Yes the ramp can be safely used
Explanation:
Here, we have
Length of longest ramp = 5 ft
Height of wall = 2 ft
Therefore, the sine of the angle adjacent to the ramp which is equal to the angle of elevation is given by;

Where:
The opposite side to angle = 2 ft wall and
Hypotenuse side = Ramp = 5 ft
Therefore,
and θ = sin⁻¹0.4 = 23.55 °
The ramp can be safely used as the angle it is adjacent to is less than the specified 30°.