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Sergio039 [100]
3 years ago
8

A large sphere has a mass of 175 kg and is suspended by a chain from the ceiling. The mass of the chain is 12.0 kg. What is the

tension in the chain?
1830, N1610, N1720, N1940 N.
Physics
1 answer:
Elina [12.6K]3 years ago
5 0

Each point in the chain supports the weight of all the mass below it.

At the bottom end of the chain, the weight is  (175 x 9.8) = 1,715 N .
At the top of the chain, the weight is  (175 + 12) x (9.8) = 1,833 N .

The tension in the chain varies linearly from  1,715N  at the bottom
to  1,833N  at the top.

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5
Ronch [10]

Answer:

Current in a parallel circuit = 0.61 amps (Approx)

Explanation:

Given:

Voltage V = 6 volt

Two resistors = 17.2 , 22.4 in parallel circuit

Find:

Current in a parallel circuit

Computation:

1/R = 1/r1 + 1 / r2

1/R = 1/17.2 + 1 / 22.4

R = 9.73 ohms (Approx)

Current in a parallel circuit = V / R

Current in a parallel circuit = 6 / 9.73

Current in a parallel circuit = 0.61 amps (Approx)

4 0
3 years ago
. Which of the following are forces that push upward on an indoor skydiver? Choose all that apply. *
SpyIntel [72]

The forces that push upward on an indoor skydiver are lift force and air resistance.

The forces that act on a skydiver moving downwards includes, gravity due to his weight, air resistance and lift force.

The downward forces on the indoor skydiver include the following;

  • <em>gravity due to its weight</em>
  • <em>downward force due its acceleration</em>

<em />

The upward force on the indoor skydiver include the following;

  • <em>lift force</em>
  • <em>air resistance</em>

Thus, we can conclude that the forces that push upward on an indoor skydiver are lift force and air resistance.

Learn more here:brainly.com/question/8947470

7 0
3 years ago
A uniform disk of mass 21 kg, thickness 0.5 m, and radius 0.6 m is located at the origin, oriented with its axis along the y axi
goldenfox [79]

Answer:

29.69 kgm^2/s

Explanation:

So suppose the axis of rotation is perpendicular to the surface of the disk, then the moment of inertia can be calculated as the following:

I = mr^2/2 = 21 * 0.6^2/2 = 3.78 kgm^2

We can convert the rotation speed in term of 0.8 seconds per revolution to the angular velocity knowing that each revolution is 2π

\omega = 2\pi / 0.8 = 7.85 rad/s

Then the rotational angular momentum of the disk is:

\omega I = 7.85 * 3.78 = 29.69 kgm^2/s

In case the axis of rotation is parallel with the surface, the moment of inertia would have a formula of:

I = m(3r^2 + h^2)/12 = 21*(3*0.6^2 + 0.5^2)/12 = 2.3275 kg m^2

5 0
3 years ago
while test flying the new f-22 raptor fighter jet, test pilot bob put the plane in a horizontal loop while flying at the speed o
sveticcg [70]

Given

v = 343 m/s

ac = 5g

ac = 5*9.8 m/s^2

ac = 49 m/s^2

where,

v: velocity

ac = centripetal aceleration

Procedure

We call the acceleration of an object moving in uniform circular motion—resulting from a net external force—the centripetal acceleration ac; centripetal means “toward the center” or “center seeking”.

Formula

\begin{gathered} a_c=\frac{v^2}{r} \\ r=\frac{v^2}{a_c} \\ r=\frac{(343m/s)^2}{49m/s^2} \\ r=2401\text{ m} \end{gathered}

The minimum radius not to exceed the centripetal acceleration is 2401 m.

8 0
2 years ago
A ramp is needed to allow vehicles to climb a 2 foot wall. The angle of elevation in order for the vehicles to safely go up must
stepan [7]

Answer:

Yes the ramp can be safely used

Explanation:

Here, we have

Length of longest ramp = 5 ft

Height of wall = 2 ft

Therefore, the sine of the angle adjacent to the ramp which is equal to the angle of elevation is given by;

Sin\theta = \frac{Opposite \, side \, to\,  angle}{Hypothenus\, side \, of\,  triangle}

Where:

The opposite side to angle = 2 ft wall and

Hypotenuse side = Ramp = 5 ft

Therefore,

Sin\theta = \frac{2}{5} = 0.4 and θ = sin⁻¹0.4 = 23.55 °

The ramp can be safely used as the angle it is adjacent to is less than the specified 30°.

5 0
4 years ago
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