Ask question

Ask question

All categories

3 years ago

13

Water flows in a smooth pipe of diameter 1 ft with a velocity of 10 ft/s. If the kinematic viscosity of the water is 1.21*10-5 f

t2/s, the headloss due to friction over a pipe length of 1000 ft is most nearly:

1 answer:

Murrr4er [49]3 years ago

5 0

Hahaqjjajajajamaajajajakla,Alaska

You might be interested in

By the mid-1980s, the prices of economy cars had risen substantially, with the smaller Japanese and American sedans costing five

mash [69]

Answer:

Cause and effect

Explanation:

In this text, the most suitable structure is a cause and effect structure. The text explains why the prices of economy cars rose substantially in the United States during the mid-1980s. The initial cause was import quotas, which led to the effect of the Japanese sending mostly luxury cars to America. This pattern is reproduced through the passage, allowing us to understand the connection between different sentences within a paragraph.

7 0

3 years ago

The 30-kg gear is subjected to a force of P=(20t)N where t is in seconds. Determine the angular velocity of the gear at t=4s sta

tatyana61 [14]

Answer:

$\omega =\frac{24}{1.14375}=20.983\frac{rad}{s}$

Explanation:

Previous concepts

Angular momentum. If we consider a particle of mass m, with velocity v, moving under the influence of a force F. The angular momentum about point O is defined as the “moment” of the particle’s linear momentum, L, about O. And the correct formula is:

$H_o =r x mv=rxL$

Applying Newton’s second law to the right hand side of the above equation, we have that r ×ma = r ×F =

MO, where MO is the moment of the force F about point O. The equation expressing the rate of change of angular momentum is this one:

MO = H˙ O

Principle of Angular Impulse and Momentum

The equation MO = H˙ O gives us the instantaneous relation between the moment and the time rate of change of angular momentum. Imagine now that the force considered acts on a particle between time t1 and time t2. The equation MO = H˙ O can then be integrated in time to obtain this:

$\int_{t_1}^{t_2}M_O dt = \int_{t_1}^{t_2}H_O dt=H_0t2 -H_0t1$

Solution to the problem

For this case we can use the principle of angular impulse and momentum that states "The mass moment of inertia of a gear about its mass center is $I_o =mK^2_o =30kg(0.125m)^2 =0.46875 kgm^2$ ".

If we analyze the staritning point we see that the initial velocity can be founded like this:

$v_o =\omega r_{OIC}=\omega (0.15m)$

And if we look the figure attached we can use the point A as a reference to calculate the angular impulse and momentum equation, like this:

$H_Ai +\sum \int_{t_i}^{t_f} M_A dt =H_Af$

$0+\sum \int_{0}^{4} 20t (0.15m) dt =0.46875 \omega + 30kg[\omega(0.15m)](0.15m)$

And if we integrate the left part and we simplify the right part we have

$1.5(4^2)-1.5(0^2) = 0.46875\omega +0.675\omega=1.14375\omega$

And if we solve for $\omega$ we got:

$\omega =\frac{24}{1.14375}=20.983\frac{rad}{s}$

8 0

3 years ago

What differentiates an athletic trainer from a clinical exercise physiologist?

kozerog [31]

Answer:

It's number 3

Explanation:

3 0

3 years ago

Read 2 more answers

Which statement below can be used to read data from a file one character at a time?

Paraphin [41]

Answer:

b

Explanation: because it says input file.read

8 0

3 years ago

The value of the critical Reynolds number for the flow over a flat plate is 5 x10^5. The significance of the value is:

nata0808 [166]

Answer:

(c) If the Reynolds number for the plate based on the length L is greater than this value, then the boundary layer is turbulent over the entire plate.

Explanation:

The applicability of the Reynolds number differs depending on the specifications of the fluid flow such as the variation of density (compressibility), a variation of viscosity (Non-Newtonian), being internal- or external flow, etc. The critical Reynolds number is the expression of the value to specify transition among regimes which diversifies regarding type of flow and geometry as well. Whilst the critical Reynolds number for turbulent flow in a pipe is 2000, the critical Reynolds number for turbulent flow over a flat plate, when the flow velocity is the free-stream velocity, is in a range from 10 raised to power 5 to 10 raised to power 6, .4

8 0

3 years ago