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3 years ago

Why are physicist hard to work a companies that design buildings

Physics

2 answers:

Hunter-Best [27]3 years ago

8 0

Answer:

a career in construction industry is not an option that springs to mind for many physics graduate

meriva3 years ago

3 0

Answer:

buildings involve matter and energy.

Explanation:

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A parallel-plate capacitor with only air between its plates is charged by connecting the capacitor to a battery. The capacitor i

Delicious77 [7]

Answer:

3.91

Explanation:

Given that

Final reading of the voltmeter, V2 = 45 v

Initial reading of the voltmeter, V1 = 11.5 v

The dielectric constant k, of a material is usually given as

k = V2/V1

k = 45 / 11.5

k = 3.91

Therefore, the dielectric constant of the material as we've calculated above is sure to be 3.91.

I hope that helps you understand

5 0

4 years ago

If I fell asleep at 9:42 pm and woke up at 10:06 am. What was the total hours of sleep I got?

gladu [14]

Answer:

11 hours and 24 minutes total of sleep. Nice.

Explanation:

Since its going from pm to am, We have to go past 12 to 1 and go to 9 hours am, then add 42 by 24 minutes to get to the 6 minutes past 10.

#teamtrees #WAP (Water And Plant)

3 0

3 years ago

Read 2 more answers

If a projectile is launched vertically from the Earth with a speed equal to the escape speed, how high above the earth's surface

Alecsey [184]

Answer: h = 3R

Explanation:

Using the law of conservation of energy,

Total energy at the beginning of the launch would be equal to total energy at any point.

kinetic energy + gravitational potential energy = constant

Initial energy of the projectile = $\frac{1}{2}mv_e^2-\frac{GMm}{R}$ ... (1)

where R is the radius of the Earth, M is the mass ofthe Earth, m is the mass of the projectile.

escape velocity, $v_e=\sqrt{\frac{2GM}{R}}$

Total energy at height h above the Earth where speed of the projectile is half the escape velocity:

$\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h}$ ...(2)

(1)=(2)

⇒ $\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h} = \frac{1}{2}mv_e^2-\frac{GMm}{R}$

⇒ $G\frac{Mm}{R}-G\frac{Mm}{R+h}= \frac{1}{2}m \frac{3}{4}v_e^2 =\frac{1}{2}m \frac{3}{4} (\sqrt{\frac{2GM}{R}})^2$

⇒ $\frac{GM(R+h-R)}{R(R+h)} = \frac{3}{4}(\frac{GM}{R})$

⇒ $\frac{h}{R+h} = \frac{3}{4}$

⇒h = 3R

Thus, at height equal to thrice radius of Earth, the speed of the projectile would reduce to half of escape velocity.

4 0

3 years ago

Read 2 more answers

(AKS 1c) A bowler rolls a bowling ball with a speed of 4 m/s. It took 2s to reach the pins at the end of the lane. What is the f

Advocard [28]

Answer:

B is the answer

Explanation:

When A is divided by 7x, it multiplies to0.81

6 0

4 years ago

une lampe soumise à une tension continue de 12V , consomme unepuissance de 1.8 W. L'intensité du courant traversant la lampe est

Eduardwww [97]

Answer:

I = 0.15 A

Explanation:

The question is "a lamp subjected to a continuous voltage of 12V , consumes a power of 1.8 W. The intensity of the current passing through the lamp is what"

Given that,

Power of the lamp, P = 1.8 W

Voltage, V = 12 V

We need to find the current through the lamp. The power of the lamp is given by :

$P=V\times I\\\\I=\dfrac{P}{V}\\\\I=\dfrac{1.8}{12}\\\\I=0.15\ A$

So, the current through the lamp is 0.15 A.

6 0

3 years ago