Question

you can use a torque feeler that consists of a meterstick held at the 0 cm end with a weight dangling from various positions along the stick. When the stick is held horizontally, torque produced when a 1 kg object hangs fromt he 50 cm mark. How much torque is exerted when the object is hung from the 75 cm mark

Answer 1

Answer:

$T=7.3575\ N.m$

Explanation:

Given:

length of the stick, $l=100\ cm=1\ m$

position of holding the stick that acts as a hinge, $f=0\ cm$

mass of the object, $m=1\ kg$

position of hanging the mass on the meter stick, $x=50\ cm=0.5\ m$

new position of hanging the mass, $x'=75\ cm=0.75\ m$

Now the torque in the initial position:

$T=mg.x$

where:

$g=$ acceleration due to gravity

$T=1\times 9.81\times 0.5$

$T=4.905\ N.m$

Now when the mass is at the new position:

$T=mg.x'$

$T=1\times 9.81\times 0.75$

$T=7.3575\ N.m$