Potential is the first blank and kinetic is the second blank.
This should be correct
Answer:
T=1022.42 N
Explanation:
Given that
l = 32 cm ,μ = 1.5 g/cm
L =2 m ,V= 344 m/s
The pipe is closed so n= 3 ,for first over tone


f= 129 Hz
The tension in the string given as
T = f²(4l²) μ
Now by putting the values
T = f²(4l²) μ
T = 129² x (4 x 0.32²) x 1.5 x 10⁻³ x 100
T=1022.42 N
Answer:
393.6m/s
Explanation:
Given parameters:
Acceleration = 8.5m/s²
Distance = 300m
Final velocity = 400m/s
Unknown:
Initial velocity = ?
Solution:
To solve this problem, we use the expression below;
v² = u² + 2as
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance
So;
v² - 2as = u²
u² = v² - 2as
u² = 400² - (2 x 8.5 x 300)
u = 393.6m/s