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DochEvi [55]
3 years ago
14

When the temperature of a metal cylinder is raised from 0.0°C to 110°C, its length increases by 0.22%. Find the percent change i

n density.
Physics
2 answers:
monitta3 years ago
8 0
<span>Volume of cylinder = pi*r*2*L

As, from the above formula,volume is directly proportional to length, 
So, if we increase in length also increases in volume by 0.22%

we know 

</span><span>density=<span><span>mass/</span><span>volume

As, density is inversely proportional to volume it means increasing in volume decreases the density by 50.22%
</span></span></span>
Umnica [9.8K]3 years ago
7 0

Answer: The percent change in density is (-0.21 %).

Explanation:

Density before raising the temperature:

\rho_1=\frac{M}{V_1}=\frac{M}{\pi r^2h}

Temperature of a metal cylinder is raised from 0.0°C to 110°C.

h'=h+0.22\%\times h=h+0.0022h=1.0022 h

\rho_2=\frac{M}{V_2}=\frac{M}{\pi r^2h'}=\frac{M}{\pi r^2(1.0022)h}

\text{percentage change}=\frac{rho_2-rho_1}{\rho_1}\times 100

\text{percentage change in density}=\frac{\frac{M}{\pi r^2(1.0022)h}-\frac{M}{\pi r^2h}}{\frac{M}{\pi r^2h}}\times 100=-0.21\%

The negative sign indicates that density had been decreased.

The percent change in density is (-0.21 %).


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In this problem we are told that the three resistors are connected in parallel. This means that their terminals are connected to the same point of the circuit: therefore, this means that they also have the same potential difference across them.

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