Answer:
20, 083 L
Explanation:
The mistake was the result of not using units when converting the 7862 l to Kg. They used the density in pounds hence they multiplied by 1.77 Lb/L and obtained 13597 Lb not Kg as they assumed.
To obtain the amount needed to refuel they subtracted this quantity from the 22,300 Kg required for the trip again obtaining the wrong quantity of 8703 Kg and they converted this to liters by dividing the density to get 4916 L and then placed then 5000 L of fuel
The quantity required was
7862 L * 1.77 Lb/L = 13915.74 Lb (pounds not kilos)
then converting this pounds to Kg by multiplying by 0.454 Kg/L one gets
6173 Kg on board
Amount Required
( 22,300 -6173) : 16127 Kg
16127 Kg/ 0.803 Kg/L = 20083 L
load every electric circuit,regardless of where it is or how large or small, has four basic parts: an energy source (ac or dc),a conductor (wire), an electrical load (device), and at least one controller(switch)
Answer:
The value of v2 in each case is:
A) V2=3v for only Vs1
B) V2=2v for only Vs2
C) V2=5v for both Vs1 and Vs2
Explanation:
In the attached graphic we draw the currents in the circuit. If we consider only one of the batteries, we can consider the other shorted.
Also, what the problem asks is the value V2 in each case, where:
If we use superposition, we passivate a battery and consider the circuit affected only by the other battery.
In the first case we can use an equivalent resistance between R2 and R3:
And
In the second case we can use an equivalent resistance between R2 and (R1+R4):
And
If we consider both batteries:
Answer:
Engineering is the use of scientific principles to design an build machines, structure, an other item including bridges, tunnels, road etc
