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Schach [20]
2 years ago
12

a capacitor is connected accross a bettery? why does each plate recieve a charge of equal to magnitude?

Physics
2 answers:
aniked [119]2 years ago
8 0
If you're talking about capacitor connected in series than the charge on each of the capacitor would be same since charge induced on the left plate of capacitor I.e +Q would then induce charge on the right plate of the capacitor as -Q (equal in magnitude but opposite charge) then again the other capacitor next to it would generate +Q charge and so on.
sineoko [7]2 years ago
5 0
Ok i hope you know how a capcitors looks and its construction , this much basic is enough, so it got two parallel plates and some diaelectric between them ,now when its connected across a battery then the battery will add some electrons on one of the plates (let's say on the upper plate) but total electrons entangled in your circuit is always constant a power source cannot create or destroy electrons it just helps the electrons to move around in the circuit and create a potential diffrence, only that !!
So  for every electron you add on the top of the plate (upper plate) you gotta remove the same amount of electron from the bottom of the plate 
which means nothing but the charge accumulated (negetive charge) on the top of the plate is equals to the charge removed from the (postive charge) bottom of the plate, and they must be equal for the conservation of charge 
This explains the phenomena nicely 
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KengaRu [80]

Answer:

40 km/h

Explanation:

First...

Look at the formula speed is equal to the distance over time or s = d/t.

Next...

Use the formula: 240/6.0

Finally...

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3 years ago
A proton moving at 8.00 106 m/s through a magnetic field of magnitude 1.72 T experiences a magnetic force of magnitude 7.20 10-1
gladu [14]

Answer:

19.1 deg

Explanation:

v = speed of the proton = 8 x 10⁶ m/s

B = magnitude of the magnetic field = 1.72 T

q = magnitude of charge on the proton = 1.6 x 10⁻¹⁹ C

F = magnitude of magnetic force on the proton = 7.20 x 10⁻¹³ N

θ = Angle between proton's velocity and magnetic field

magnitude of magnetic force on the proton is given as

F = q v B Sinθ

7.20 x 10⁻¹³ = (1.6 x 10⁻¹⁹) (8 x 10⁶) (1.72) Sinθ

Sinθ = 0.327

θ = 19.1 deg

4 0
3 years ago
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laiz [17]

Answer:

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8 0
2 years ago
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tia_tia [17]

Answer:

B = 0.75 T

Explanation:

As we know that the force on a moving charge in magnetic field is given by the formula

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F = 4.8 \times 10^{-13} N

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now from above equation we have

B = \frac{4.8 \times 10^{-13}}{(1.6 \times 10^{-19})(4 \times 10^6)}

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I think it could be A
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